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4 years ago

Solve the literal equation for y a=9y-3yx

Mathematics

2 answers:

Novay_Z [31]4 years ago

6 0

$a=9y-3yx\\\\a=y\big(9-3x\big)\quad|:\big(9-3x\big)\\\\\\\boxed{y=\frac{a}{9-3x}}\qquad \text{for}\quad x\neq 3$

BigorU [14]4 years ago

5 0

Answer:

The value of the equation for y is $y=\frac{a}{9-3x}$ .

Step-by-step explanation:

Consider the provided equation.

$a=9y-3yx$

We need to solve the equation for y.

Take common y from right side.

$a=y(9-3x)$

Divide both the sides by 9-3x.

$\frac{a}{9-3x}=\frac{y(9-3x)}{9-3x}$

$y=\frac{a}{9-3x}$

Hence, the value of the equation for y is $y=\frac{a}{9-3x}$ .

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Write an equation of a line in slope intercept form (y = mx + b) going through the points

Alexeev081 [22]

Answer:

y = - $\frac{1}{2}$ x - 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (4, - 3)

m = $\frac{-3-0}{4+2}$ = $\frac{-3}{6}$ = - $\frac{1}{2}$ , thus

y = - $\frac{1}{2}$ x + b ← is the partial equation

To find b substitute either of the 2 points into the partial equation

Using (- 2, 0 ), then

0 = 1 + b ⇒ b = 0 - 1 = - 1

y = - $\frac{1}{2}$ x - 1 ← in slope- intercept form

5 0

4 years ago

A particular electronic component is produced at two plants for an electronics manufacturer. Plant A produces 70% of the compone

Vesna [10]

Answer:

If a component received by the manufacturer is defective, the probability that it was produced at plant A is 0.5385 = 53.85%.

Step-by-step explanation:

We use the Bayes Theorem to solve this question.

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Defective component

Event B: Produced at plant A.

Plant A produces 70% of the components used

This means that $P(B) = 0.7$

Among the components produced at plant A, the proportion of defective components is 1%.

This means that $P(A|B) = 0.01$

Probability of a defective component:

1% of 70%(defective at plant A)

2% of 100 - 70 = 30%(defective at plant B). So

$P(A) = 0.01*0.7 + 0.02*0.3 = 0.013$

If a component received by the manufacturer is defective, the probability that it was produced at plant A is

$P(B|A) = \frac{0.7*0.01}{0.013} = 0.5385$

If a component received by the manufacturer is defective, the probability that it was produced at plant A is 0.5385 = 53.85%.

4 0

3 years ago

How much more would $1000 earn in 5 years in an account compounded continuously than an account compounded quarterly if the inte

choli [55]

$\bf ~~~~~~ \textit{Compounding Continuously Interest Earned Amount}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$1000\\
r=rate\to 3.7\%\to \frac{3.7}{100}\to &0.037\\
t=years\to &5
\end{cases}
\\\\\\
A=1000e^{0.037\cdot 5}\implies A=1000e^{0.185}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3.7\%\to \frac{3.7}{100}\to &0.037\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &5
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.037}{4}\right)^{4\cdot 5}\implies A=1000(1.00925)^{20}$

compare both amounts.

8 0

3 years ago

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svlad2 [7]

Im not sure about this one but i think x is 60 since the line Ed basically bisects the angle E which also bisects the line GH in half so that 62=x+2 and then solve for the equation

7 0

4 years ago

Cecil and his brother played in the park on Tuesday.they played soccer for 3/4 of an hour and tennis for 1/8 of an hour. How lon

natima [27]

Answer:

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Step-by-step explanation:

3 0

3 years ago