Y=.05x +4100
Y=.05(3)+4100
Y=.15+4100
Y=4100.15
Answer:
Sue = 25.75
Dave = 29.5
Tom = 19.75
Sue = s
Tom = t
Dave = d
Step-by-step explanation:
s+t+d = 75
s-6=t
d +16 = s+t
d+16+d= 75
2d = 59
d = 29.5
t = s-6
t+s = 45.5
s-6+s= 45.5
2s = 51.5
s= 25.75
t= 19.75
Answer:
18.0167≤x≤21.9833
Step-by-step explanation:
Given the following
sample size n = 10
standard deviation s = 3.2
Sample mean = 20
z-score at 95% = 1.96
Confidence Interval = x ± z×s/√n
Confidence Interval = 20 ± 1.96×3.2/√10
Confidence Interval = 20 ± (1.96×3.2/3.16)
Confidence Interval = 20 ± (1.96×1.0119)
Confidence Interval = 20 ± 1.9833
CI = {20-1.9833, 20+1.9833}
CI = {18.0167, 21.9833}
Hence the required confidence interval is 18.0167≤x≤21.9833
