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Vitek1552 [10]
2 years ago
6

The A+ Cell Company charges $40 per month and $0.30 per minute for each additional minute over 500 minutes. The cost can be writ

ten as a linear function, C(x)=0.3x+40, where x is the number of minutes over 500. If the company were to increase the $40 charge to $50, how would the graph of this function change?
The graph will move _____ units.

answers are: up 10, down 10, left .10, right .10
Mathematics
1 answer:
adelina 88 [10]2 years ago
8 0

Answer:

up 10

Step-by-step explanation:

The function would change from

C(x) = 0.3x + 40

to

C(x) = 0.3x + 50

The change is only to the y-intercept, so the graph of the function will move up 10.

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Answer:

The rate of change of the weight of kitten A is greater than the rate of change of the weight of kitten B

Step-by-step explanation:

  • The rate of change of the linear relationship is the slope of the line which represent this relationship
  • The rule of the slope is m = \frac{y2-y1}{x2-x1} , where (x1, y1) and (x2, y2) are 2 points on the line

∵ The table shows the weight gain of kitten A

→ Choose two points from the table to find the slope

∵ Points (0, 3) and (1, 7) are two points in the table

∴ x1 = 0 and y1 = 3

∴ x2 = 1 and y2 = 7

→ Substitute them in the rule of the slope above

∵ m = \frac{7-3}{1-0} = \frac{4}{1} = 4

∵ The slope is the rate of change

∴ The rate of change of the weight of kitten A is 4 oz/week

∵ The graph shows the weight gain of kitten B

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→ Substitute them in the rule of the slope above

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∵ The slope is the rate of change

∴ The rate of change of the weight of kitten B is 3 oz/week

→ By comparing the two rates

∵ The rate of change of kitten A is 4 oz per week

∵ The rate of change of kitten B is 3 oz per week

∴ The rate of change of the weight of kitten A is greater than

   the rate of change of the weight of kitten B

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