The complete question is
<span>Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr and then for another 2 hours and 5 minutes with a constant speed of 12 km/hr what is her average speed for the total trip?</span>
we know that
speed=distance/time
1) Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr
time=2 1/6 hrs----> 13/6 hrs
speed=6 km/h
distance=speed*time----> 6*(13/6)---> 13 km
2)for another 2 hours and 5 minutes with a constant speed of 12 km/hr
time=2hrs+5 minutes----> 2+(5/60)--> 125/60 hrs
speed=12 km/hrs
distance=speed*time----> 12*(125/60)---> 25 km
3) find the average speed for the total trip
total distance=13 km+25 km----> 38 km
total time=(13/6)+(125/60)----> (10*13+125)/60----> 4.25 hours
speed=38/4.25----> 8.94 km/hrs
the answer is
8.94 km/hrs
Answer and Step-by-step explanation:
4 hours on Monday, so subtract 4 from 16.
We get 12.
So now it says twice as many on Saturday as on Thursday
So two numbers that add up to 12, but one number is twice the other number, would be 4.
4 times 2 is 8, and 4 + 8 is 12. 12 + 4 = 16
8 is the answer.
Kyle works 8 hours on Saturday.
Since 8 is twice the amount of 4, and 8 + 4 + 4 equals 16.
<em><u>#teamtrees #PWA (Plant And Water)</u></em>
We need to write an expression for the operations:
![\begin{gathered} \text{ multiply 7 by 8} \\ \\ \text{dived f by the result} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7B%20multiply%207%20by%208%7D%20%5C%5C%20%20%5C%5C%20%5Ctext%7Bdived%20f%20by%20the%20result%7D%20%5Cend%7Bgathered%7D)
The first operation (multiplication) can be represented as:
![7\cdot8](https://tex.z-dn.net/?f=7%5Ccdot8)
The second operation (the division of f by the previous result) can be represented as:
![f\div(7\cdot8)](https://tex.z-dn.net/?f=f%5Cdiv%287%5Ccdot8%29)
Notice that we need the parenthesis to indicate that the product is the first operation to be done.
Answer:
<span> 2/4 simplified would equal 1/2</span>