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lara [203]
3 years ago
7

Which function grows at the fastest rate for increasing values of x? g(x)=14x p(x)=12x3+9 f(x)=2x2−x h(x)=3x

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0
The function that is growing at the fastest rate is p(x) = 12x^3 + 9.

This is a cubic function, meaning that x is raised to the third power. This is the only function that is raised to the third power, so it will increase the fastest.
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3 0
3 years ago
Given the circle with the diameter of 33 cm find the area of the circle
exis [7]

Answer:

51.81 cm^2

Step-by-step explanation:

Find The Half Of 33 which is 16.5

Use The Formula For Area

A= \pi x r^2

A= 3.14 x 16.5

A= 51.81 cm^2

3 0
2 years ago
Which of the
kondor19780726 [428]

The pic is attached.

7 0
2 years ago
Read 2 more answers
⚠️⚠️⚠️⚠️⚠️ 15 points
Helga [31]

Answer:

The answer is (4x-1)·(3x+2)

Step-by-step explanation:

3 0
3 years ago
A student solves the following equation and
Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}

\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)

\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)

\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)

as

  • \frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)
  • -\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a
  • \frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2

so equation becomes

3\left(a-2\right)-6a=a+2  

-3a-6=a+2

-3a-6+6=a+2+6

-4a=8

\mathrm{Divide\:both\:sides\:by\:}-4

\frac{-4a}{-4}=\frac{8}{-4}

a=-2

\mathrm{Verify\:Solutions}

\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}

\mathrm{Solve\:}\:a+2=0:\quad a=-2

\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2

\mathrm{Solve\:}\:a-2=0:\quad a=2

So the following points are undefined

a=-2,\:a=2

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0
3 years ago
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