Question

In the Ridgeland Park youth athletics program, 60% of athletes play baseball and 24% of athletes play baseball and basketball.

Answer 1

It is 0.4 for the awnser

Answer 2

Answer:

The percentage of the athletes who play baseball also play basketball is 40 %.

Step-by-step explanation:

Let A is the event that athlete plays baseball and B is the event that the athlete plays basketball,

According to the question,

The probability of being baseball player, P(A) = 60 % = 0.6

Also, the  probability of being baseball player as well as basketball player, P(A∩B) = 24 % = 0.24,

Hence, the probability that athletes who play baseball also play basketball,

$P(\frac{B}{A})=\frac{P(A\cap B)}{P(A)}=\frac{0.24}{0.6}=0.4=40\%$

Therefore, the percentage of the athletes who play baseball also play basketball is 40%.