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3 years ago

State when the following equation and inequalities will be true and when they will be false.

Mathematics

1 answer:

Andreas93 [3]3 years ago

7 0

All you need to do is solve it.
36=9k
4=k

so it is true when 4=k and false when k>4 or k<4.

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From his house, Tom rides his bike 5 kilometers east to the store. He then rides his bike 2 kilometers west to his friends house

mario62 [17]

Answer:

3 km

Step-by-step explanation:

He starts by going 5 km east, then he turns around and goes 2 km west. So he is now 3 km from his house.

7 0

2 years ago

A line intersects the point (6,9) and (7,4). What is the slope intercept equation for this line?

taurus [48]

Answer:

y = -5x + 39

Step-by-step explanation:

Plug either ordered pair into the Point-Slope Formula FIRST, y - y₁ = m(x - x₁), then convert to Slope-Intercept Form by moving whichever term is nearest to y, over to the right side of the equivalence symbol to get the above answer.

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3 years ago

Investigate to cell phone plans (Koodo v.s. Chatr) and determine which one is most cost and user- efficient for my everyday need

ELEN [110]

Go to photomath the app

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3 years ago

Lisa is standing on a dock beside a lake. She drops a rock from her hand into the lake. After the rock hits the surface of the l

yawa3891 [41]

Well, it goes 5 inches per second so after 4 seconds it is 4 times 5 =20 inches under the surface, add that to 5 feet and you get 6 ft and 8 inches

5 0

3 years ago

On a trip, a motorist drove 150 miles in the morning and 50 miles in the afternoon. His average rate in the morning was twice hi

Lina20 [59]

Answer:

Morning's average rate = 50 mph, and Afternoon's average rate = 25 mph.

Step-by-step explanation:

Suppose he drove 150 miles for X hours, then his average rate in the morning was (150/X) mph.

Given that he spent 5 hours in driving.

And he drove 50 miles for (5-X) hours, then his average rate in the afternoon was 50/(5-X) mph.

Given that his average rate in the morning was twice his average rate in the afternoon.

(150/x) = 2 * 50/(5-x)

150/x = 100/(5-x)

Cross multiplying terms, we get:-

150*(5-x) = 100*x

750 - 150x = 100x

750 = 100x + 150x

750 = 250x

x = 750/250 = 3.

It means he spent 3 hours in the morning and 2 hours in the afternoon.

So morning's average rate = 150/3 = 50 mph.

and afternoon's average rate = 50/(5-3) = 25 mph.

8 0

3 years ago