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4 years ago

A bakery sells cakes for $23 and a dozen cupcakes for

Mathematics

1 answer:

lys-0071 [83]4 years ago

8 0

Answer:

23x + 18y = 1446

x + y = 72

Step-by-step explanation:

The bakery made $1446 total. We represent this as the cost of each cake ($23) times the number of cakes sold (x) plus the cost of each dozen cupcakes ($18) times the number of cupcakes sold (y).

Thus, 23x +18y = $1446.

The bakery sold 72 items total. We represent this as the number of cakes sold (x) plus the number of each dozen cupcakes sold (y).

Thus, x + y = 72.

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Rhett made $250 washing cars with his mobile car wash company. He charges $70 per car and earned $50 in tips. Write an equation

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HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

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