x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Step-by-step explanation:
We need to solve the equation
and find values of x.
Solving:
Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)
Multiply the entire equation with x(x-1)

Now, factoring the term:

The values of x are x=1 and x=2
Checking for extraneous roots:
Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.
If we put x=1 in the equation,
the denominator becomes zero i.e
which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.
If we put x=2 in the equation,


So, x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Keywords: Solving Equations and checking extraneous solution
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The answer to this would be C because you can multiply everything by 3 and still have a consistent-dependent system.
Answer:
Add ak190 smart answer
Step-by-step explanation:
Answer:
34
Step-by-step explanation:
-5y=-45
y=-45/-5
=9
y=9
then
5y-11=5×9-11
=45-11
=34
Answer:
2nd option will be the answer (y=4x²+48x+146)
Step-by-step explanation:
y=4(x+6)²+2
y=4(x²+2*x*6+6²)+2 [(a+b)²=a²+2ab+b²]
y=4(x²+12x+36)+2
y=4(x²)+4(12x)+4(36)+2
y=4x²+48x+144+2
y=4x²+48x+146