Answer:
The correct answer is B, the second option
Step-by-step explanation:
(-2, 5/3)
Solve for the first variable in one of the equations, then substitute the result into the other equation.
(a) Let
denote the amount of sugar in the tank at time
. The tank starts with only pure water, so
.
(b) Sugar flows in at a rate of
(0.07 kg/L) * (7 L/min) = 0.49 kg/min = 49/100 kg/min
and flows out at a rate of
(<em>A(t)</em>/1080 kg/L) * (7 L/min) = 7<em>A(t)</em>/1080 kg/min
so that the net rate of change of
is governed by the ODE,

or

Multiply both sides by the integrating factor
to condense the left side into the derivative of a product:


Integrate both sides:


Solve for
:

Given that
, we find

so that the amount of sugar at any time
is

(c) As
, the exponential term converges to 0 and we're left with

or 75.6 kg of sugar.
Evet hocam proje konularını da bir bir insan değilim ki bir uyu bir insan bir arar bir insan bir şey var
Answer:
1) 1023
2) 8
Step-by-step explanation:
1)
Given:
and 
Then, the next table can be computed (only the first terms are explicitely shown)
n 
1 1
2
3
3
7
4 15
5 31
6 63
7 127
8 255
9 511
10 1023
2)
Given

Then, the next table can be computed
n 
1
-1
2
0
3
3
4
8