I think that all of the above are correct.
if you have to pick 1. i would suggest that you pick A.
dose this help?
The answer is <span>a. Each gene is at the same locus on both chromosomes.
Since e</span><span>ach gene is at the same locus on both chromosomes, they are able to pair correctly before they separate in meiosis. They never produce identical phenotypes. Also, the genes and alleles on the homologous chromosomes are not identical. </span>
Using intracellular pH (pHi) imaging, we investigated Cl transport mechanisms in freshwater rainbow trout gill mitochondrion-rich (MR) cells. In isolated MR cells, scanning electron microscopy has shown that cellular polarity is maintained.
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What is Transport in Two Species of Freshwater Fish?</h3>
Large amounts of diluted water constantly flow across the gill epithelium of freshwater fish, causing them to experience an ionic stress. Since the mechanisms of ion and acid-base transport are connected at the gill, this is made worse by an acid-base disruption. Active transport at specialised mitochondrion-rich (MR) cells on the gill surface helps the fish maintain homeostasis. As a result, the freshwater gill has served as a crucial model system for figuring out the transport processes that allow for the overriding of adverse ion gradients. Numerous research have tried to clarify the mechanisms of ion and acid-base transport in freshwater fishes during the past ten years using a range of methodologies.
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Answer:
Hardy-Weinberg equilibrium AND IF you assume that red hair is a simple recessive trait, then
q^2 = 0.12
q = 0.35 and p = 0.65
p^2 would equal proportion of population that is homozygous = 0.42, so 42% of the population is homozygous for non-red hair.
Explanation:
i looked it up on google
