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Alexxx [7]
2 years ago
13

The question is the photo.

Mathematics
2 answers:
andrew-mc [135]2 years ago
7 0

Answer:

w=5

Step-by-step explanation:

the triangle has the same size of area as the side of the rectangle so therefore 5

Liono4ka [1.6K]2 years ago
7 0

Answer:

The area of a triangle is A\Delta=\frac{1}{2}(base)(height)

So, the area of the given triangle is:

A\Delta=\frac{1}{2}(5)(6)\\A\Delta=\frac{1}{2}(30)\\A\Delta=15cm^2

The area of a rectangle is

A=(length)(width)\\A=(6)w\\A=6wcm^2

Once the area of both are the same:

6w=15\\w=\frac{15}{6} \\w=2.5cm

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Using the z-distribution, it is found that the lower bound of the 99% confidence interval is given by:

d. 68.39%.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

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  • z is the critical value.
  • n is the sample size.

In this problem, we have a 99% confidence level, hence\alpha = 0.99, z is the value of Z that has a p-value of \frac{1+0.99}{2} = 0.995, so the critical value is z = 2.575.

The sample size and estimate are given by:

n = 2002, \pi = 0.71

Hence, the lower bound is given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.71 - 2.575\sqrt{\frac{0.71(0.29)}{2002}} = 0.6839

Hence the lower bound is of 68.39%, which means that option D is correct.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
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Suppose you are standing such that a 32-foot tree is directly between you and the sun. If you are standing 140 feet away from th
Ghella [55]

Answer:

Height = 4 feet

Step-by-step explanation:

To determine how tall I can be we take the difference between the shadow cast by the 32-feet tree and the distance away from the tree

But the tree is 32 feet tall but on shadow it's 160

So lemme determine how long I'll be in my shadow first

Distance away from tree= 140 feet

Length of shadow cast by tree

= 160 feet

Length of shadow= 160-140

Length if shadow= 20 feet

My height= x

X/20= 32/160

X= 20*32/260

X = 4 feet

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3 0
2 years ago
How do i graph the parabolas y = 1/32x^2
Pachacha [2.7K]
y=\frac{1}{32}x^2 \\ \\x=-16 \Rightarrow  y=\frac{1}{32} *(-16)^2=\frac{1}{\not32^1}*\not256^8=8\\ \\x=-8 \Rightarrow  y=\frac{1}{32} *(-8)^2=\frac{1}{\not32^1}*\not64^2=2\\ \\x=0 \Rightarrow  y=\frac{1}{32} *(0)^2=\frac{1}{\not32^1}*0=0 \\ \\x=8 \Rightarrow  y=\frac{1}{32} *(8)^2=\frac{1}{\not32^1}*\not64^2=2 \\ \\x= 16 \Rightarrow  y=\frac{1}{32} *( 16)^2=\frac{1}{\not32^1}*\not256^8=8

7 0
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lbvjy [14]

Answer:

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