Imagine a model shaded to show 0.001 How much would be shaded?

What is the probability of drawing a 9 of spades from a 52-card deck given the deck is properly shuffled?

avanturin [10]

1.923% (Roughly)

You can get this by dividing 1 by 52 to find the likelihood.

4 0

3 years ago

Graph the following piecewise function:

zhenek [66]

Check the picture below.

notice the solid circle at -4 and 3, since it includes those points.

also notice the dashed line, though the lines keeps on going those ways, is not included in the piece-wise, since it's not part fo the domain or constraints.

5 0

3 years ago

15 3/4% is equal to which decimal? A- 0.1575 B- 157.25 C-15.25 D- 15.34

eimsori [14]

15 3/4% = 15.75%
15.75% = 0.1575
The answer is A.

6 0

3 years ago

Read 2 more answers

Can you please answer the question?

Roman55 [17]

The trigonometric expression $\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$ is equivalent to the trigonometric expression $\sec \alpha \cdot \csc \alpha + 1$ .

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that one side of the equality is equal to the expression of the other side, requiring the use of algebraic and trigonometric properties. Now we proceed to present the corresponding procedure:

$\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}$

$\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}$

$\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}$

$\tan \alpha + 1 + \cot \alpha$

$\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1$

$\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1$

$\frac{1}{\cos \alpha \cdot \sin \alpha} + 1$

$\sec \alpha \cdot \csc \alpha + 1$

The trigonometric expression $\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$ is equivalent to the trigonometric expression $\sec \alpha \cdot \csc \alpha + 1$ .

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

6 0

2 years ago

A locker combination has three nonzero digits and digits cannot be replaced. The first two digits are 9 and 8. What is the proba

Deffense [45]

Answer:

1 in 7

Step-by-step explanation:

Your one-digit choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.

But they're nonzero, so: 1, 2, 3, 4, 5, 6, 7, 8, 9.

But they can't be repeated and 9 and 8 are used, so: 1, 2, 3, 4, 5, 6, 7.

Only 7 numbers left, so chances are, 1 in 7.

8 0

3 years ago