Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So,
is 37°. We can see from the diagram that
would be
143°.
Also, the new bearing is N 25°E. So,
would be 25°.
Now we can find
. As the sum of the internal angle of a triangle is 180°.

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
180°
Step-by-step explanation:
The sum of angles in any triangle is 180°
Answer:
y = 0.625x+3.625
Step-by-step explanation:
<h3>
Answer: G) -2</h3>
=======================================================
Explanation:
I'm assuming you meant to say (a+y)^2 + 2y
Replace each copy of 'a' with 5. Replace each copy of 'y' with -3. Use PEMDAS to simplify.
(a+y)^2 + 2y
(5 + (-3))^2 + 2(-3)
(5-3)^2 + 2(-3)
(2)^2 + 2(-3)
4 + 2(-3)
4 - 6
-2
So (a+y)^2 + 2y = -2 when a = 5 and y = -3.
Answer:
a) 0.8333
b) 0.75
c) 0.8181 or 0.9090
Step-by-step explanation:
a)
The probability the visitor selects an authentic painting is
10/12 = 0.8333
b)
Since the opinion of the expert does not depend on your choice, the events are <em>independent</em>, so the probability that the expert says is authentic and it really is, is
0.8333*0.9 = 0.75
c)
If the expert decides the painting is a copy and it is not, then there are 11 paintings of which 9 are authentic, so the probability the visitor selects a new original painting is
9/11= 0.8181
If the expert decides the painting is a copy and it is, then there are 11 paintings of which 10 are authentic, so the probability the visitor selects a new original painting is
10/11= 0.9090