<u>Formula</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Given</u><u> </u><u>that </u><u>:</u><u>-</u><u> </u>
The interest received on Rs 5000 = interest received on Rs 6000 , when rate of interest on Rs 6000 is 8 % .
<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u><u> </u>
The rate of interest on rupees 5000 .
<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u><u> </u>
→ S.I = P.R.T/100
→ 5000.R. 1 / 100 = 6000 × 8 × 1 / 100
→ 50 R = 60×8
→ 50 R = 480
→ R = 480/ 50
→ Rate of interest = 9.6 %
So rate on Rs 5000 is 9.6 %
Answer:
Step-by-step explanation:
I'm assuming you're asking for most simplified form?
Original Equation:
Rewrite sqrt(27) using the exponent property:
Simplify sqrt(9)
Rewrite the radical sqrt(12)
Simplify sqrt(2)
Rewrite the radical sqrt(48)
Simplify the sqrt(16)
You can think of sqrt(3) as x, in which case you have 3x - 2x + 4x, so you just add the coefficients and leave the sqrt(3) alone.
Subtract 2 from 3
Add 1 and 4
Answer:
56x² + 2xy+ 3y²
Step-by-step explanation:
81x²+18xy+18xy+4y² - (25x²+10xy+y²) = 56x² + 2xy+ 3y²
Answer:
The volume of a bar of gold with a mass of 66.5 grams is
Step-by-step explanation:
Given , mass(in grams) ∝ Volume (in cm3)
Here, volume of 95 grams bar = 5cm3
So, thevolume of 1 gram bar = =
⇒The volume of a bar with weight 66.5 grams =
So, the volume of a bar of gold with a mass of 66.5 grams is