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4 years ago

What is the formula for finding the slope when given two points?

Mathematics

1 answer:

fredd [130]4 years ago

7 0

Answer:

The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept. If you know two points that a line passes through, this page will show you how to find the equation of the line.

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What is the graph of 5x = 2y − 20?

Viefleur [7K]

5x4=20 i think this is the right one

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4 years ago

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True or false a rectangle is a parallelogram with a right interior angle?

oee [108]

I definitely would say True.

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3 years ago

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Solve the equation 905=5a

Annette [7]

905=5a

905/5=5a/5

181=a

HOPE THIS HELPS!!!!!!!!!!

7 0

3 years ago

Read 2 more answers

Let <img src="https://tex.z-dn.net/?f=%5Csf%20a%2Bb%2Ca-b%2Cab%2C%5Cdfrac%7Ba%7D%7Bb%7D" id="TexFormula1" title="\sf a+b,a-b,ab,

Black_prince [1.1K]

Answer:

171/40 or 4 11/40

Step-by-step explanation:

<h3>AP given</h3>

a + b, a - b, ab, a/b

6th term

<h3>Solution</h3>

Common difference

<u>Difference of first two</u>

d = (a -b) - (a + b) = -2b

<u>Difference of second two</u>

d= ab - (a - b)

<u>Difference of last two</u>

d = a/b - ab

<u>Now comparing d:</u>

-2b = ab - (a - b)
ab - a = - 3b
a(1 - b) = 3b
a = 3b/(1 - b)

and

a/b - ab = -2b
a(1/b - b) = -2b
a = 2b²/(b² - 1)

<u>Eliminating a:</u>

2b²/(b² - 1) = 3b/(1 - b)
2b/(b+1) = -3
2b = -3b - 3
5b = - 3
b = -3/5

<u>Finding a:</u>

a = 3b/(1 - b) =
3*(-3/5) *1/(1 - (-3/5)) =
-9/5*5/8 =
-9/8

<u>So the first term is:</u>

a + b = -3/5 - 9/8 = -24/40 - 45/40 = - 69/40

<u>Common difference:</u>

d = -2b = -2(-3/5) = 6/5

a₆ = a₁ + 5d =
-69/40 + 5*6/5 =
-69/40 + 240/40 =
171/40 = 4 11/40

8 0

3 years ago

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

4 years ago