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3 years ago

HELP HELP HELP PLEASE!!!!! What is the area of this polygon?

Mathematics

2 answers:

Vsevolod [243]3 years ago

7 0

You pressed on the correct answer

Andrei [34K]3 years ago

4 0

Answer: 35.5 $unit^2$

Step-by-step explanation:

For finding the area of this polygon we can divide it into triangles and rectangle,

By the below diagram,

The area of this polygon = Area of rectangle having dimension 4× 3 + Area of triangle having base 4 unit and height 3 unit +Area of triangle having base 7 unit and height 3 unit + Area of triangle having base 7 unit and height 2 unit,

= $12 + \frac{1}{2}\times 4\times 3 + \frac{1}{2}\times 7\times 3 + \frac{1}{2}\times 7\times 2$

= $12 + 6 + 10.5 + 7$

= $35.5\text{ square unit}$

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A triangle measures 12 degrees and 40 degrees what is the measurement of the 3rd angle of the triangle

Vinvika [58]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{128°}}}}}$

Step-by-step explanation:

Sum of angles of triangle add up to 180°

Let the third angle be x

Create an equation and solve for x

$\sf{x + 12° + 40° = 180°}$

$\dashrightarrow{ \sf{x + 52° = 180°}}$

$\dashrightarrow{ \sf{x = 180° - 52°}}$

$\dashrightarrow{ \boxed{\sf{x = 128°}}}$

Hope I helped!

Best regards! :D

3 0

4 years ago

9. Raymond and Rose were working with exponents. Part A: Raymond claims that 5^5 * 5^2 = 5^3. Rose argues that 5^5 * 5^2 = 5^7.

tamaranim1 [39]

Answer: Rose is correct 5^5*5^2=5^7

Step-by-step explanation:

when multiplying two powers that have the same base you can add the exponent s (product property’s)

6 0

3 years ago

Please please help me with this!

viktelen [127]

Answer:

b less than 1

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

4.Is it sometimes, always, or never true that, if A and B both have dimensions n x n , AB=BA ? Explain.

REY [17]

Answer: Is true sometimes.

Step-by-step explanation:

I guess that here we have two matrices, A and B, that are nxn.

We can see that if those matrices can conmutate, then we can try it with some simple matrices.

$A = \left[\begin{array}{ccc}1&0\\0&-1\end{array}\right] . B = \left[\begin{array}{ccc}2&0\\1&1\end{array}\right]$

Here, we would have that:

$AB = \left[\begin{array}{ccc}2&0\\-1&-1\end{array}\right]$

$BA = \left[\begin{array}{ccc}2&0\\1&-1\end{array}\right]$

You can see that AB and BA are different, then the statement is not always true.

But it is true sometimes, if A or B are the identiti, then I*A = A*I, in this case would be true.

It is also true if A and B are diagonal matrices, let's prove it:

$A = \left[\begin{array}{ccc}a&0\\0&b\end{array}\right] , B = \left[\begin{array}{ccc}c&0\\0&d\end{array}\right]$

$AB = \left[\begin{array}{ccc}ac&0\\0&bd\end{array}\right] = BA$

5 0

4 years ago

The number of <img src="https://tex.z-dn.net/?f=x" id="TexFormula1" title="x" alt="x" align="absmiddle" class="latex-formula"> s

Alex777 [14]

Answer:

D. 4

Step-by-step explanation:

Without actually solving the equation, recall that for $a=|b|$ , there are two cases:

$\begin{cases}a=b, \\a=-b\end{cases}$

In the given equation $|x-2|^{10x^2-1}=|x-2|^{3x}$ , there are two pairs of absolute value symbols.

Since each has two cases, there must be a total of $2\cdot 2=\boxed{4}$ different equations created.

All four cases are:

$\begin{cases}(x-2)^{10x^2-1}=(x-2)^{3x},\\(-x+2)^{10x^2-1}=(x-2)^{3x},\\(x-2)^{10x^2-1}=(-x+2)^{3x},\\(-x+2)^{10x^2-1}=(-x+2)^{3x}\end{cases}$

Exponents differ, hence clearly there are four possible solutions to this equation.

You can solve for all four values of $x$ by taking the log of both sides and using a bit of algebra to verify you have four solutions.

5 0

3 years ago