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The volume occupied by this oxygen gas is equal to 10.0 Liters.
<u>Given the following data:</u>
- Mass of oxygen gas = 4.8 grams
- Pressure = 0.50 atm
- Temperature = 133°C to Kelvin =
- Molar mass of oxygen gas =
= 31.998 g/mol.
<u>Scientific data:</u>
- Ideal gas constant, R = 0.0821 L⋅atm/mol⋅K
To determine the volume occupied by this oxygen gas:
First of all, we would calculate the number of moles of oxygen gas;
Number of moles = 0.15 moles.
Now, we can determine the volume by using the ideal gas law equation;
<u>Where;</u>
- P is the pressure.
- V is the volume.
- n is the number of moles of a gas.
- R is the ideal gas constant.
- T is the temperature.
Substituting the given parameters into the formula, we have;
Volume, V = 9.9998 ≈ 10.0 Liters.
Read more on volume here: brainly.com/question/25290815