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dlinn [17]
3 years ago
9

How do I simplify an expression using the distributive property?

Mathematics
1 answer:
vladimir2022 [97]3 years ago
4 0
You multiply the number outside the parenthesis with both of the numbers in the parenthesis separately.
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Please help thanks have a great day
ELEN [110]

Answer:

-7

Step-by-step explanation:

i think so

if correct

marke brianliest

3 0
3 years ago
Sally purchased a Pokemon game for $10.50, and a racing game for $6.50 with a $20 bill. How much change did Sally get?
pantera1 [17]

Answer:

$3

Step-by-step explanation:

1. Add the total of the price. 10.50+6.50=17 The total of the items cost $17.

2. Subtract the cost from the amount you are paying. 20-17=3 Sally gets $3 of change.

7 0
3 years ago
Read 2 more answers
Please help me! And please explain how to solve this. Especially questions B, C, and E
kati45 [8]
A. radical 76 is8.6 so  false
B. 3 radical 10 is 9.4  true
C. 4 radical 2 is 5.6 so false
D. radical 29 is 5.3 so true
E. 2 radical 50 is 14.14 so false
5 0
4 years ago
A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be
irga5000 [103]

Answer:

The statement is now presented as:

\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

Step-by-step explanation:

Let C = (h,k) the coordinates of the center of the circle, which must be transformed into C'=(h', k') by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

(x-h)^{2}+(y-k)^{2} = r^{2}

Where r is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) <em>Center of the circle is translated 4 units to the right</em> (+x direction):

C''(x,y) = C(x, y) + U(x,y) (Eq. 1)

Where U(x,y) is the translation vector, dimensionless.

If we know that C(x, y) = (h,k) and U(x,y) = (4, 0), then:

C''(x,y) = (h,k)+(4,0)

C''(x,y) =(h+4,k)

2) <em>Reflection over the x-axis</em>:

C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)] (Eq. 2)

Where O(x,y) is the reflection point, dimensionless.

If we know that O(x,y) = (h+4,0) and C''(x,y) =(h+4,k), the new point is:

C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]

C'(x,y) = (h+4, 0)-(0,k)

C'(x,y) = (h+4, -k)

And thus, h' = h+4 and k' = -k. The statement is now presented as:

\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

<em />

4 0
3 years ago
Nicholas bought three business related books. His total bill was $150. If one book cost him 50% more than the other two books co
goldenfox [79]
The price of this more expensive book was $90.00 ($150 - $60) based on the date acquired from the question above. This problem can be solved using a simple algebra equation which consisted of one variable. The equation is stated as $150 = x + 1.5x (x = $150/2.5 = $60) where x is the price of the cheaper book and 1.5x is the price of the more expensive books because it has 50% higher price than the cheaper book<span>.</span>
4 0
3 years ago
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