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Sholpan [36]
3 years ago
15

In a direct variation equation f(x) = 6 when x = 4. what is the direct variation equation

Mathematics
2 answers:
aksik [14]3 years ago
8 0

Answer:

C-f(x)=1.5x

just took the quiz and 3/2 reduces to 1.5

KiRa [710]3 years ago
5 0

Answer:

D) f(x)=1.5x

Step-by-step explanation:

Direct variation is the opposite of Proportional Variation. It is given according to this formula:

y=kx

The notation f(x) = y. Since f(x)=y= 6 and x=4 Firstly let's find k. Then plug it back to the original one.

We have:

y=kx\\6=k4\\k=\frac{6}{4} =k=\frac{3}{2}\\y=\frac{3}{2}x \Rightarrow y\approx1.5x

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Step-by-step explanation:

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54 - 54 + 9y = -18 + 54

9y = 36 isolate y

9y/9 = 36/9

y = 4

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Find the surface area of the prism.
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Step-by-step explanation:

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2 years ago
You drive 30 miles due east in a half hour. Then, you turn left and drive 30 miles north in 1 hour. What are your average speed
garri49 [273]
Original position: P1=(0,0)
<span>You drive 30 miles due east in a half hour: x=+30 miles, t1=1/2 hour=0.5 hours
</span><span>Then, you turn left and drive 30 miles north in 1 hour: y=+30 miles, t2=1 hour
Rectangular coordinates of final position: P2=(x,y)→P2=(30,30)
Total time: t=t1+t2=0.5 hours+1 hour→t=1.5 hours

Average speed: S ave=d/t
Total distance: d=x+y=30 miles+30 miles→d=60 miles
S ave = 60 miles / (1.5 hours)
S ave = 40 miles/hour

Velocity is a vector, the magnitude of this vector is the magnitude of the vector of change of position dividing by the total time t
The vector of change of position: s=P1-P2=(30,30)-(0,0)=(30-0,30-0)→
s=(30,30) 
Magnitude of vector s=sqrt[30^2+30^2]=sqrt[30^2*2]=sqrt[30^2]*sqrt(2)
Magnitude of vector s=30*sqrt(2) miles

Magnitude of velocity vector = Magnitud of vector s / t
Magnitude of velocity vector = [30*sqrt(2) miles] / (1.5 hours)
Magnitude of velocity vector = 20*sqrt(2) miles / hour
Magnitude of velocity vector=20*1.4142 miles / hour
Magnitude of velocity vector=28.284 miles/hour

Polar coordinates of your position=(r, theta)
r=Magnitude of vector s=30*sqrt(2) miles
theta=tan^(-1) (y/x) = tan^(-1) [(30 miles) / (30 miles)]
theta=tan^(-1) (1)→theta=45°=Pi/4 (Pi=3.1416)
Polar coordinates of your position: ( 30*sqrt(2) miles, 45°)
Polar coordinate of your position: ( 30*sqrt(2) miles, Pi/4 )

Answers:
Average speed: 40 miles / hour
Velocity: 20*sqrt(2) miles / hour = 28.284 miles / hour
Rectangular coordinates of your position = (30,30)
Polar coordinates of your position=(30*sqrt(2) miles,45°)
Polar coordinates of your position=(30*sqrt(2) miles,Pi/4)</span>
4 0
3 years ago
How are the power rules for quotients and products similar? How are they different? Refer specifically to the way that the rule
Effectus [21]
There are several other rules that go along with the power rule.such as the products to power rule and the quotient to power rule.
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