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melisa1 [442]
3 years ago
7

The solution for x2+2x+8<0

Mathematics
2 answers:
Tema [17]3 years ago
7 0
Answer for this question is the zeros are greater than -4 and 2
ziro4ka [17]3 years ago
7 0

Answer:

The answer is indeed the empty set, just answered the question :)

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write and solve an equation to determine the length of a rectangular prism with a width of 4 feet ,a height of 6 feet ,and a vol
Tasya [4]

Answer:

3.5ft

Step-by-step explanation:

To calculate the volume of something, you need to know the formula. Length x width x height. You already know the width, and the height, so you need to find the length.

4ft x 6ft x 3.5ft = 84ft^3

3 0
3 years ago
Haaaalppppppppppppppppp
Marizza181 [45]

Answer:

50-2.5t=w. no, the water will all have drained by then.

Step-by-step explanation:

2.5 per min so

min=t

therefore 2.5t

theres 50 quarts of water

50-2.5t = w (water left in the tank)

_____________________________________-

part 2,

2.5*30 = 75, and 50<75

this is impossible.

7 0
3 years ago
Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
3 years ago
If you have 10 apples what where is the 9th one?
FromTheMoon [43]
To Your First Nine Friends, You Give Them 1 Apple Each. Your Tenth Friend, You Give Her The Basket With The Tenth Apple. She Has The Apple, And The Basket?
5 0
3 years ago
Can someone tell me how to work it out or the answer please
muminat

Answer:

Answer is 1.706992967

8 0
2 years ago
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