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DIA [1.3K]
4 years ago
10

Please help due tomorrow fith grade math

Mathematics
2 answers:
Sladkaya [172]4 years ago
6 0
Please retake the photo, a lot of people would love to help you but we need a different photo
xeze [42]4 years ago
3 0
I would answer it if I could, but the image is blurry. Try remaking the picture a bit more clearly, please. 
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Help me please!!!!!!!
Daniel [21]
C.4 is the right answer
6 0
4 years ago
Can someone please expand and simplify this
laila [671]

Pasos  

3(3−1)

Usa la propiedad distributiva para multiplicar 3 por 3−1.

(3)2−3

El cuadrado de 3 es 3.

3−3

B

Pasos  

5(10+2)

Usa la propiedad distributiva para multiplicar 5 por 10+2.

510+52

Factorice 10=5×2. Vuelva a escribir la raíz cuadrada del producto 5×2 como el producto de las raíces cuadradas 52.

552+52

Multiplica 5 y 5 para obtener 5.

52+52

Para multiplicar 5 y 2, multiplique los números bajo la raíz cuadrada.

52+10

4 0
2 years ago
At a local grocery store, bananas were on sale. Green bananas were priced at $14.00 and yellow bananas were priced at $12.00. Sa
garri49 [273]

Answer:

Sabrina bought 6 yellow bananas and 3 green bananas

Step-by-step explanation:

Let

Green bananas = x

Yellow bananas = y

Green bananas = $14.00

Yellow bananas = $12.00

Total cost = $114.00

x + y = 9 (1)

14x + 12y = 114 (2)

From (1)

x = 9 - y

Substitute x = 9 - y into (2)

14(9 - y) + 12y = 114

126 - 14y + 12y = 114

- 14y + 12y = 114 - 126

-2y = -12

Divide both sides by -2

y = -12 / -2

= 6

y = 6

Substitute y = 6 into (1)

x + y = 9

x + 6 = 9

x = 9 - 6

= 3

x = 3

Sabrina bought 6 yellow bananas and 3 green bananas

3 0
3 years ago
4) Mandy has a flower garden that is 30
Softa [21]

Answer:

using quaderatic expression solving problems of algebraic expressions.

Step-by-step explanation:

no1.

take the smallest side to be x

and the longest side to be x-1/3

then expand the expression equating to 30.

then solve for x value

6 0
2 years ago
How do I solve this, please help
Bas_tet [7]

9514 1404 393

Answer:

  • EF = DE = 44
  • FG = DG = 36
  • FH = DF = 31

Step-by-step explanation:

Since EH is the perpendicular bisector of DF, ∆DEF is isosceles and sides DE and EF have the same length.

  DE = EF

  (9x -1) = (7x +9)

  2x = 10 . . . . . . . add 1-7x

  x = 5 . . . . . . . . . divide by 2

__

Similarly, marked sides GD and GF are the same length, so ...

  GD = GF

  (10y -4) = (7y +8)

  3y = 12 . . . . . . . . . . add 4-7y

  y = 4 . . . . . . . . . divide by 3

__

Now, we have what we need to calculate the side lengths.

  EF = 7x+9 = 7·5 +9 = 44

  DE = 9x-1 = 9·4 -1 = 44

  FG = 7y+8 = 7·4 +8 = 36

  DG = 10y-4 = 10·4 -4 = 36

  FH = 3x+4y = 3·5 +4·4 = 31

  DF = FH = 31

6 0
3 years ago
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