A = 21/2 i will write something too just to fill up the space
1) Solve one of the equations for either variable.
2) Substitute the expression from Step 1 into the other equation.
3) Solve the resulting equation.
4) Substitute the solution in Step 3 into one of the original equations to find the other variable.
5) Write the solution as an ordered pair.
Two events are occurring:
1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3
Probability of getting an odd number = 3/6
2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2
The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12
Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario.
So correct answer is option C
Answer:
Step-by-step explanation:
you have a 29 of 38 chance at lossing
Your answer is E. $25.
First let under 12 = u, over 12 = o, and adults = a.
We can now write the equations:
2u + 3a + 3o = 174
4u + 2a = 122
a + o = 46
Because we know that a + o = 46, and 3a + 3o is in the first equation, we can multiply 46 by 3 to get what 3a + 3o equals. This makes 138.
Now we can substitute 138 into the first equation to get 2u + 138 = 174
2u = 36
u = 18
Now that we know what u equals, we can substitute it in to the second equation to get:
4(18) + 2a = 122
72 + 2a = 122
2a = 50
a = $25
I hope this helps! Let me know if you have any questions :)
