Which method can't you use to solve the problem: x^2 - 47= 0
2 answers:
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Given a = 3 and b = - 8 ,
= > 2b² - 4a + 4a²
= > 2( - 8 )² - 4( 3 ) + 4( 3 )²
= > 2( 64 ) - 4( 3 ) + 4( 9 )
= > 128 - 12 + 36
= > 116 + 36
= > 152
= > 2b² - 4a + 4a²
= > 2( - 8 )² - 4( 3 ) + 4( 3 )²
= > 2( 64 ) - 4( 3 ) + 4( 9 )
= > 128 - 12 + 36
= > 116 + 36
= > 152
Answer:
All options are correct.
Step-by-step explanation:
In option (A), the given equation is
Add 37 on both sides.
Subtract x from both sides.
LHS=RHS for all values of x. It means equation x-37=x-37 has infinite many solutions.
Similarly.
In option (B), the given equation is
LHS=RHS for all values of x. It means equation 73x-37=73x-37 has infinite many solutions.
In option (C), the given equation is
LHS=RHS for all values of x. It means equation 37x-37=37x-37 has infinite many solutions.
In option (D), the given equation is
LHS=RHS for all values of x. It means equation 74x-37=74x-37 has infinite many solutions.
Therefore, all options are correct.