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3 years ago

Draw a model... write an equation and solve....this is the directions for a 4th grade math homework problem....Help?????

1 answer:

6 0

Boxers = b
Spaniels = s

$b=s*4$
$s+b=30$

Now you have two equations - one that tells you the number of boxers in relation to spaniels and one telling you the number of each breed in relation to the total number of dogs. Solve using substitution.

$s+(4*s)=30 \\ 4s+s=30 \\ 5s=30 \\ s=6$

There are 6 spaniels.

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Q4 Q14.) Solve the following exponential equation by expressing each side as a power of the same base and then equating exponent

sashaice [31]

Hello there!

Let me try this one out!

$6 ^{x-6} = \frac{1}{1296}$

We can start by taking log of both sides

$log(6 ^{x-6}) = log( \frac{1}{1296})$

$(x - 6)(log(6)) = log( \frac{1}{1296})$

Since we are solving for x:

$x - 6 = \frac{log(1/1296)}{log(6)}$

I used a calculator to help me solve the right part :)

x - 6 = - 4

Now we can add 6 on both sides

x - 6 + 6 = - 4 + 6

x = 2

I hope this helps! Let me know if you have any questions about the answer.

4 0

4 years ago

A company has a cost equation of c=0.925x^2-4x+20 and a profit equation of p=-1.125x^2+6x+40. Solve for the breakeven point.

lana66690 [7]

0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40 (at break even point)

2.05x^2 - 10x - 20 = 0

x = [ - (-10) +/- sqrt(100 - 4*2.05*-20) / (2*2.05)

x = 6.40, -1.52 Ignore the negative

Answer is 6.40

3 0

3 years ago

Equation for -10p+9p=12

Marizza181 [45]

p= -12 is your answer

5 0

3 years ago

Read 2 more answers

1 and 3/4 as an improper fraction

expeople1 [14]

7/4 you do this because, for example you can think of it like pizza and pizza slices. You have 1 pizza and 3/4 of a pizza, let’s say each slice is 1/4 of a pizza. How many slices do you have altogether? Seven. You can also think of 1 as 4/4, so the just add 3/4 + 4/4 (which is technically just 3+4) = 7/4

3 0

3 years ago

Read 2 more answers

10 .find the partial sum S10 of the arithmetic series with a1 = 4, d = 5.

Crazy boy [7]

Answer:

S10 = 320

Step-by-step explanation:

The formula for calculating the sum of the nth term of an AP is expressed as

Sn = n/2(2a+(n-1)d))

Given

a = 4

d = 5

n = 10

S10 =10/2{2(5)+(10-1)5}

S10 =5{10+9(6)}

S10 =5{10+54}

S10 = 5(64)

S10 = 320

Hence the sum of the first ten terms of the sequence is 320

8 0

3 years ago