According to the confidence interval only persons who watch at least 9.9 hours TV per day are eligible.
According to the statement
we have given that the mean of 7 hours per day watching TV, and a standard deviation of 1.8 hours.
And we have to find that the At least how many hours of daily TV watching are necessary for a person to be eligible for the interview.
So, For this purpose,
The confidence interval is is a range of estimates for an unknown parameter. A confidence interval is computed at a designated confidence level.
Let us Assume x is the amount of hours that 5% of the persons exceeds.
Then P(z<(x-7)/1.8) = 0.95
From a standard normal table, we know that:
(x-7)/1.8 = 1.6449
x-7 = 2.9607
x = 9.9607
So, According to the confidence interval only persons who watch at least 9.9 hours TV per day are eligible.
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f(x) is an exponential growth function. It can be modeled as
, where a is the initial amount, r is the interest rate in decimal form, and t is the time period. When the values from the scenario are plugged in, it looks like
. On a graph, a will be the y-intercept, so the
y-intercept of f(x) is 6.
g(x) has a y-intercept that must be less than 6. The function reaches a y-value of 6 when x = 1, not 0 (when x = 0, we are given the y-intercept). We see that as y decreases x decreases, so it is confirmed that g(x) has a
y-intercept that is < 6. Already we know that its y-intercept is less than that of f(x).
h(x) visibly intercepts the y-axis at y = 4. Its
y-intercept is 4.
j(x) is written in exponential growth format (like f(x)), where the initial amount, <em>a</em>, would be the y-intercept.
10 is its y-intercept.
After evaluating the y-intercepts of each of these functions, it is determined that
j(x) has the highest y-intercept.
546 divide by 6 = 91 so 91 times 6 = 546
The total trip at 55 km per hour is 55 km per hour x 6 hours = 330 km.
Total time for the rip at 50 km per hour is 330 km / 50 km per hour = 6.6 hours.
1 hour = 60 minutes. 60 minutes x 0.6 hours = 36 minutes loner.