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Mrrafil [7]
3 years ago
14

I don't understand and I need this done someone please help

Mathematics
1 answer:
borishaifa [10]3 years ago
8 0
You must first attach the problems with your question.
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What value of y satisfies the system of equations:<br><br> y=-6x+2<br><br> y=x^2+11
Nataly [62]

Answer:

The value of y that satisfies the system of equations is 20

Step-by-step explanation:

we have

y=-6x+2

y=x^{2}+11

we know that

The solution of the system of equations is the intersection point both graphs

using a graphing tool

the intersection point is (-3,20)

see the attached figure

therefore

The value of y that satisfies the system of equations is 20

8 0
3 years ago
A researcher wants to check the claim that convicted burglars spend less than 18.7 months in jail, on average. She takes a rando
vivado [14]

Answer:

a. No, there is not enough evidence to support the claim using a level of significance of 1%.

b. Null Hypothesis, H_0 : \mu \geq 18.7 months  

c. Alternate Hypothesis<u>,</u> H_A : \mu < 18.7 months

d. P-value of hypothesis test = 0.0199 or 1.99%

e. We conclude that the convicted burglars spend more than or equal to 18.7 months in jail, on average.

Step-by-step explanation:

We are given that a researcher wants to check the claim that convicted burglars spend less than 18.7 months in jail, on average.

She takes a random sample of 67 such cases from court files and finds that the mean is 16.8 months with a standard deviation of 7.3 months.

<em><u>Let </u></em>\mu<em><u> = true mean time convicted burglars spend in jail.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \geq 18.7 months   {means that the convicted burglars spend more than or equal to 18.7 months in jail, on average}

<u>Alternate Hypothesis,</u> H_A : \mu < 18.7 months   {means that the convicted burglars spend less than 18.7 months in jail, on average}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean time spent in jail = 16.8 months

             s = sample standard deviation = 7.3 months

             n = sample of cases = 67

So, <em><u>test statistics</u></em>  =   \frac{16.8-18.7}{\frac{7.3}{\sqrt{67} } }  ~ t_6_6

                               =  -2.13

Hence, the value of test statistics is -2.13.

<u>Now, P-value of the test statistics is given by;</u>

      P-value = P( t_6_6 < -2.13) = 0.0199 or 1.99%

  • If the P-value of test statistics is more than the level of significance, then we will not reject our null hypothesis as it will not fall in the rejection region.
  • If the P-value of test statistics is less than the level of significance, then we will reject our null hypothesis as it will fall in the rejection region.

<em>Now, here the P-value is 0.0199 or 1.99% which is clearly higher than the level of significance of 1%, so we will not reject our null hypothesis as it will not fall in the rejection region.</em>

Therefore, we conclude that the convicted burglars spend more than or equal to 18.7 months in jail, on average.

6 0
3 years ago
The width of a field is 3 miles less than the length. The square mileage of the plot is 18 miles squared. Find the dimensions.
kherson [118]
LW = A
L(L - 3) = 18
L^2 - 3L - 18 = 0
(L - 6) (L + 3) = 0
L could be 6 or -3 ( -3 cannot be a length of a side of a rectangle since it’s negative.)
So L = 6 and W= 3
6 0
3 years ago
What is the area of the circle below? Use π = 3.14 to solve. Round your answer to the nearest hundredth.
dezoksy [38]

Answer:

803.84 ft ²

:)

3 0
3 years ago
Read 2 more answers
Find the area of the square in inches and enter your answer below. Do not
Bumek [7]

Given:

Side length of square = 2 in

To find:

The area of the square

Solution:

Area of the square:

Area = side × side

        = 2 in × 2 in

Area = 4 in²

Therefore, the area of the square is 4 inches².

8 0
3 years ago
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