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4 years ago

what is 5 feet 11 inch to cm?

Mathematics

1 answer:

irga5000 [103]4 years ago

4 0

I think it is
180.34 <span>centimeters</span>

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Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the

ludmilkaskok [199]

By Stokes' theorem,

$\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S$

where $\mathcal C$ is the circular boundary of the hemisphere $\mathcal M$ in the $y$ - $z$ plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

$\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle$

where $0\le t\le2\pi$ . Then the line integral is

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt$
$=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi$

We can check this result by evaluating the equivalent surface integral. We have

$\nabla\times\mathbf f=\langle1,0,0\rangle$

and we can parameterize $\mathcal M$ by

$\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle$

so that

$\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv$

where $0\le v\le\dfrac\pi2$ and $0\le u\le2\pi$ . Then,

$\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi$

as expected.

7 0

3 years ago

A recipe for sabayon calls for 2 egg yolks, 3 tablespoons of sugar, and 1⁄4 cup of white wine. After cracking the eggs, you star

Annette [7]

Answer:

Step-by-step explanation:

A recipe for sabayon calls for 2 egg yolks, 3 tablespoons of sugar, and ¼ cup of white wine. After cracking the eggs, you start measuring the sugar, but accidentally put in 4 tablespoons of sugar. How can you compensate?

Note that we put in 4/3 more sugar than we wanted, because 3(4/3) = 4

So we need to increase eveything else by 4/3

So 2(4/3) = 8/3 = 2 +2/3 egg yolk and (1/4)(4/3) =4/12 = 1/3 cup of wine

3 0

4 years ago

Could anyone help with this question?

Nikitich [7]

Answer:

I just answered this question, In case you missed it, here it goes again:

Values for the coefficient in the product k:

$a=b=c=d=3*10^8$ , so the first four boxes should be filled with the number "3"

Drop down arrow: "does"

Step-by-step explanation:

We perform all the products of wavelength time frequency indicated for the column of the quantity "k":

$a$ = $1 * 10^{-10} * 3\, * 10^{18} = 3 * 10^{-10+18} = 3 * 10^{8}$ =

$b=1 * 10^{-1}*3*10^9=3* 10^{-1+9}=3*10^8$

$c=600*10^{-6}*5*10^{11}=3000*10^{-6+11}=3000*10^5=3*10^3*10^5=\\=3*10^{3+5}=3*10^8$

$d=4*10^{-7}*7.5*10^{14}=30.0*10^{-7+14}=30*10^7=3*10*10^7=\\=3*10^{1+7}=3*10^8$

Therefore, all products of these different wavelengths and their associated frequencies render the exact same answer : $3*10^8$ , which means that as one of these quantities increase, the other one will decrease in the same proportion to give the same numerical answer.

This means that the two quantities are associated via inverse proportionality. As seen in the equation below, if the quantities "x" and "y" are related by inverse proportionality (shown as one equals a constant "A" divided by the other variable), their product x*y will give that constant value "A" (which in our case is $3*10^8$ .

$x=\frac{A}{y} \\x*y=A$

8 0

3 years ago

HELP!!! Worth 50 points

sergejj [24]

Answer:

with what

Step-by-step explanation:

I am confused there is no question at all showing

4 0

3 years ago

Andrew estimated the weight of his dog to be 60 lb. The dog’s actual weight was 68 lb. What was the percent error in Andrew’s es

arsen [322]

The equation for percent error is: $|\frac{Experimental - Accepted}{Accepted}| * 100$

60 lb is the experimental and 68 lb is the accepted.

Plug in you values...

$| \frac{60-68}{68}| * 100$ ≈ 11.76 %

8 0

4 years ago