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Papessa [141]
3 years ago
3

What is the difference between -96.43-(-98.67)?

Mathematics
2 answers:
Yuki888 [10]3 years ago
5 0
-96.43-(-98.67)=-96.43+98.67=2.24

Ne4ueva [31]3 years ago
4 0

Answer:

The answer is C. 2.24

Step-by-step explanation:

It's right on Edgenuity, hope this helps! :)

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Triangle XYZ is shown, where n ≥ 5. Triangle X Y Z is shown. The length of side X Y is n + 4, the length of side Y Z is 2 n, and
motikmotik

Answer:

The longest side of the triangle is YZ, the shortest side is ZX, the largest angle is ∠X and the smallest angle is ∠Y.

Step-by-step explanation:

The lengths of the sides of the triangle XYZ are as follows:

XY = n + 4

YZ = 2n

ZX = n - 2

According to the triangle inequality theorem, the sum of two sides of a triangle is always greater than the third side.

Then,

XY < YZ + ZX ⇒ n + 4 < 2n + n - 2 ⇒ n + 4 < 3n - 2 ⇒ 2n > 6 ⇒ n > 3

YZ < XY + ZX ⇒ 2n < n + 4 + n - 2 ⇒ 2n < 2n + 2 ⇒ 0 < 2

ZX < XY + YZ ⇒ n - 2 < n + 4 + 2n ⇒ n - 2 < 3n + 4 ⇒ 2n > -6 ⇒ n > -3

It is provided that <em>n</em> ≥ 5.

Then the sides of the triangle are:

XY = n + 4 ≥ 5 + 4 = 9

YZ = 2n ≥ 2 × 5 = 10

ZX = n - 2 ≥ 5 - 2 = 3

So, the longest side of the triangle is YZ. And the shortest side is ZX.

The largest angle of a triangle is opposite to the longest side.

The angle opposite to YZ would be X. So, the largest angle is ∠X.

The smallest angle of a triangle is opposite to the shortest side.

The angle opposite to ZX would be Y. So, the smallest angle is ∠Y.

Thus, the longest side of the triangle is YZ, the shortest side is ZX, the largest angle is ∠X and the smallest angle is ∠Y.

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A school fair ticket costs $8 per adult and $1 per child. On a certain day, the total number of adults (a) and children (c) who
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Describe how the graph of y= x2 can be transformed to the graph of the given equation. y = x2 + 8
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When you add 8 to the end of a function formula, the graph moves UP 8 units.  This is often called either a translation or vertical shift.

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3 years ago
Assume that x is a binomial random variable with nequals80 and pequals0.5. Use a normal approximation to find each of the follow
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Answer:

Step-by-step explanation:

666

3 0
3 years ago
A bank is trying to determine which model of safe to install. The bank manager believes that each model is equally resistant to
alexandr402 [8]

Answer:

So on this case the 95% confidence interval would be given by (-1.152;5.152).

-1.152 < \mu_{safe1}-\mu_{safe2}  

Should we conclude that the average time it takes experts to crack the safes does not differ by model at the 5% significance level?

A) Yes, the 95% confidence interval for ?D contains 0.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution

Let put some notation  

x=value for Safe 1 , y = value for Safe 2

x: 103, 90, 64, 120, 104, 92, 145, 106, 76

y: 101, 94, 58, 112, 103, 90, 140, 110, 74

The first step is calculate the difference d_i=x_i-y_i and we obtain this:

d: 2, -4, 6, 8, 1, 2, 5, -4, 2

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{18}{9}=2

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =4.093

The next step is calculate the degrees of freedom given by:

df=n-1=9-1=8

Now we need to calculate the critical value on the t distribution with 8 degrees of freedom. The value of \alpha=1-0.95=0.05 and \alpha/2=0.025, so we need a quantile that accumulates on each tail of the t distribution 0.025 of the area.

We can use the following excel code to find it:"=T.INV(0.025;8)" or "=T.INV(1-0.025;8)". And we got t_{\alpha/2}=\pm 2.31

The confidence interval for the mean is given by the following formula:  

\bar d \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

Now we have everything in order to replace into formula (1):  

2-2.31\frac{4.093}{\sqrt{9}}=-1.152  

2+2.31\frac{4.093}{\sqrt{9}}=5.152  

So on this case the 95% confidence interval would be given by (-1.152;5.152).

-1.152 < \mu_{safe1}-\mu_{safe2}  

Should we conclude that the average time it takes experts to crack the safes does not differ by model at the 5% significance level?

A) Yes, the 95% confidence interval for D contains 0.

5 0
3 years ago
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