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Lady_Fox [76]
2 years ago
8

Write a simplified expression that represents the perimeter of an irregular quadrilateral with some de lengths (2 1/4t - 5) (4t

+ 3) (1/2t - 1) (3t + 2)
Mathematics
1 answer:
hjlf2 years ago
8 0

Answer:

Perimeter = \frac{39t-4}{4}

Step-by-step explanation:

Given

Lengths: (2\frac{1}{4}t - 5), (4t + 3), (1/2t - 1), (3t + 2)

Required

Determine the perimeter

The perimeter is calculated as the sum of the lengths of the irregular shape.

i.e.

Perimeter = (2\frac{1}{4}t - 5) + (4t + 3) + (1/2t - 1) + (3t + 2)

Remove brackets

Perimeter = 2\frac{1}{4}t - 5 + 4t + 3 + 1/2t - 1 + 3t + 2

Collect Like Terms

Perimeter = 2\frac{1}{4}t +4t + 1/2t + 3t - 5 + 3 - 1 + 2

Perimeter = 2\frac{1}{4}t +4t + 1/2t + 3t -1

Convert mixed number to improper fraction.

Perimeter = \frac{9}{4}t +4t + 1/2t + 3t -1

Take LCM

Perimeter = \frac{9t + 16t + 2t + 12t}{4} -1

Perimeter = \frac{39t}{4} -1

Take LCM

Perimeter = \frac{39t-4}{4}  <em>--- The perimeter of the shape</em>

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Given segments AB and CD intersect at E.
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<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

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\mathbf{D = (2, 1)}

So, we have:

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If AB bisects CD, then:

\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

\mathbf{CD = \frac 12 \times AB}

The above equation is not true, because:

\mathbf{3 \ne \frac 12 \times 3\sqrt 2}

Hence, CD does not bisect AB

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