Question

According to the general equation for conditional probability, if P(AD) =4/7 and P(B)= 7/8, what is P(A B)?

Answer 1

It is given that $P(A\cap B)=\frac{4}{7} \\ P(B)=\frac{7}{8}$

Now, the conditional probability,

$P(A|B)=\frac{P(A \cap B)}{P(B)} =\frac{4/7}{7/8} =\frac{32}{49}$.

The correct choice is (C).