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worty [1.4K]
3 years ago
12

-2 + 3x > -23 | x = ?

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

Give Me Brainliet

Step-by-step explanation:

x= 9/8 =1.125

PolarNik [594]3 years ago
7 0

Answer:

3*x-2>-23

Step-by-step explanation:

i think thats the answer

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She bought x number of $7 cd and used and $10 gift card so
7x-10=32
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5 0
3 years ago
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(5a + a2 - 14) (10a + a2 + 39)
yan [13]
15a+a4+25 is the answer
8 0
3 years ago
2(4y-5)=70<br><br>how u do this​
steposvetlana [31]

Answer:

Step-by-step explanation:

First you distribute so two times 4Y is 6Y then you multiply the two in the five which gives you 2Y -5 equals 70

3 0
4 years ago
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Find the distance between points P(5, 1) and Q(1, 3) to the nearest tenth.
bonufazy [111]

Answer:

Idk if its multiple choice but you can do 1 of 2 ways theres using distance formula =√(5-3)sq+(1-4)sq

=√4+9

=√13 <--

or

3.6 units

Given: The two points that are P(5,1) and Q(3,4).

To find: The distance between these two points.

Solution: It is given that there are two points that are P(5,1) and Q(3,4).

The distance between these two points can be found out as using the distance formula that is: 3.6

Thus, the distance between the given two points is 3.6 units.

So you choose 13 or 3.6 Hope this helps :)

3 0
3 years ago
Write the series using summation notation.<br><br> 4 + 8 + 12 + 16 + 20+ . . . + 80
zhannawk [14.2K]

Answer:

\sum ^{20} _{n \to \11} 4n

Step-by-step explanation:

In order to write the series using the summation notation, first we need to find the nth term of the sequence formed. The sequence generated by the series is an arithmetic sequence as shown;

4, 8, 12, 16, 20...80

The nth term of an arithmetic sequence is expressed as Tn = a +(n-1)d

a is the first term = 4

d is the common difference = 21-8 = 8-4 = 4

n is the number of terms

On substituting, Tn = 4+(n-1)4

Tn = 4+4n-4

Tn = 4n

The nth term of the series is 4n.

Since the last term is 80, L = 4n

80 = 4n

n = 80/4

n = 20

This shows that the total number of terms in the sequence is 20

According to the series given 4 + 8 + 12 + 16 + 20+ . . . + 80 , we are to take the sum of the first 20terms of the sequence. Using summation notation;

4 + 8 + 12 + 16 + 20+ . . . + 80  = \sum ^{20} _{n \to \11} 4n

4 0
3 years ago
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