<u>Answer:
</u>
The probability of rolling a number greater than 4 or less than 3 is 
<u>Solution:
</u>
In the given question there are two events as follows:
(a) Rolling a number greater than 4 i.e. A = {5,6}
(b) Rolling a number less than 3 i.e. B = {1,2}
Since a die has 6 numbers,
P(A) =
where P(A) is the probability of occurrence of event A and P(B) = 
Since, Event A and Event B has nothing in common therefore they are mutually exclusive events.
P(A∪B) = P(A) + P(B)



Therefore the probability of getting a number greater than 4 or less than 3 is 
Answer:
0.15866 is the probability of the average fracture strength of selected 100 pieces of glasses that of exceed 14.3.
Step-by-step explanation:
Given that, the strength of a tempered(x) a glass has average 14.1 and has standard deviation 2.
, 
n=number of selected pieces= 100.
The probability that the average fracture strength of 100 pieces of this glass exceed 14.3 is



= 1 - 0.84134
=0.15866.
The third graph or bottom left graph represents 
Step-by-step explanation:
Step 1:
To determine which of the given graphs represents the equation
, we substitute some values in the place of x.
When

Anything with an exponent of 0 will equal 1.
So the graphs on the right side cannot be the answers.
Step 2:
Now we substitute another value to determine which graph represents 
When

The value of f(x) when
is lesser than the value of f(x) when 
So the third graph or bottom left graph represents 
Find the median first. The middle of all the numbers.
5, 7, 8, 10, 11, 13, 14, 18, 27
11 is the median.
Then find the median of the upper quartile.
The upper quartile consists of numbers...
5, 7, 8, 10
Since it is an even set of numbers add the two in the middle and divided by two. So 7 plus 8= 15/2.
7.5 is your upper quartile.
PART A
The equation of the parabola in vertex form is given by the formula,

where

is the vertex of the parabola.
We substitute these values to obtain,

The point, (3,6) lies on the parabola.
It must therefore satisfy its equation.




Hence the equation of the parabola in vertex form is

PART B
To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

This implies that

We expand to obtain,

This will give us,


This equation is now in the form,

where

This is the standard form