4. Multiply. Write each answer in simplest form: (-3/4)(1/2)(-2/3)

Given AQRS-AXYZ, what is the value of tan(Q)? A) 3/5 B) 3/4 C) 4/5 D) 4/3

iren [92.7K]

The answer is B.

Since ΔQRS ~ ΔXYZ, the value of tan(Q) is :

∠Q = ∠X
tan(Q) = tan(X)
tan(X) = 3/4
tan(Q) = 3/4

3 0

2 years ago

What are the domain restrictions of the expression g2−7g+10g3−6g2+8g ? Select each correct answer.

Sauron [17]

Answer with Step-by-step explanation:

We are given that an expression

$f(g)=\frac{g^2-7g+10}{g^3-6g^2+8g}$

We have to find domain restriction of the given function.

$f(g)=\frac{(g-5)(g-2)}{g(g-4)(g-2)}$

Domain restriction means : It is that value of x when substitute in function then function will not defined.

It means it is that values which makes denominator zero.

From given function we can see that

When substitute g=0 then it makes denominator zero.

Hence, the function is not defined at g=0

Substitute g=4

Then, it makes denominator zero.

Hence, function is not defined at g=4

Substitute g=2

Then,it makes denominator zero.

Hence, function is not defined at g=2

Therefore, the function is defined for all values of g except g=0, g=2 and g=4

5 0

3 years ago

15% of what number is equal to 9

just olya [345]

The percentage of 15% of 9 is 60% (I think)

8 0

2 years ago

Read 2 more answers

Cassandra shared her post with 3 friends, who each shared it with 3 more friends. They continued sharing at the same rate.

uranmaximum [27]

F(3) = 3(3)
f(3) 3f
f(10) 10

5 0

2 years ago

Read 2 more answers

In a certain Algebra 2 class of 30 students, 14 of them play basketball and 10 of them play baseball. There are 14 students who

Veseljchak [2.6K]

Answer:

In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.

But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?

Thank you for all of the help.

That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)

So: the two events are not independent, and so that formula doesn't work.

Fortunately, a formula that does work (always!) is:

P(A∪B)=P(A)+P(B)−P(A∩B)

Hence:

P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330

7 0

2 years ago