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valkas [14]
4 years ago
14

A group of 40 students from your school is part of the audience for a tv game show. The total number of people in the audience i

s 150. What is the theoretical probability of 5 students from your school being selected as contestants out of 8 possible spots
Mathematics
2 answers:
jenyasd209 [6]4 years ago
3 0
18.75% chance they will be picked
makkiz [27]4 years ago
3 0

Answer:

2.7% theoretical probability of 5 students from your school being selected as contestants out of 8 possible spots

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the students are picked is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes:

5 from your school, from a group of 40.

3 from others schools, from a group of 150-40 = 110. So

D = C_{40,5}C_{110,3} = \frac{40!}{5!(40-5)!}\frac{100!}{3!(100-3)!} = 142011286560

Total outcomes:

8 students, from a group of 150. So

T = C_{150,8} = \frac{150!}{8!(150-8)!} = 5.2572114 \times 10^{12}

Probability:

p = \frac{D}{T} = \frac{142011286560}{5.2572114 \times 10^{12}} = 0.0270

2.7% theoretical probability of 5 students from your school being selected as contestants out of 8 possible spots

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A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib
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Answer:   0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

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As per given ,

Population mean weight of 50 people = \mu=50\times190=9500\text{ pounds}

Standard deviation of 50 people =\sigma=40\sqrt{50}=40(7.07106781187)=282.84

Then , the probability its maximum safe load will be exceeded =

P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855

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3 0
4 years ago
Which statements describe a parallelogram that must be a rhombus?
earnstyle [38]

Answer:

3 and 5.

Step-by-step explanation:

A parallelogram which is a rhombus has perpendicular diagonals.

Also a parallelogram which is a rhombus has a pair of congruent consecutive sides.

6 0
3 years ago
With food prices becoming a great issue in the world; wheat yields are even more important. Some of the highest yielding dry lan
Rzqust [24]

Answer:

Option E) 61.6

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100 bushels per acre

Standard Deviation, σ = 30 bushels per acre

We assume that the distribution of yield is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(X>x) = 0.90

We have to find the value of x such that the probability is 0.90

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 100}{30})=0.90  

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Calculation the value from standard normal table, we have,  

P(z

\displaystyle\frac{x - 100}{30} = -1.282\\x = 61.55 \approx 61.6  

Hence, the yield of 61.6 bushels per acre or more would save the seed.

7 0
3 years ago
A baseball team played 32 games and lost 8. Katy was a catcher in 5/8 of the winning game and 1/4 of the losing games. In how ma
lana66690 [7]

32 - 8 = 24. This means that there were 24 winning games and 8 losing games.

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8 multiplied by 1/4 = 2. Katy was a catcher in 2 of the losing games.

In total, Katy was a catcher in 17 of the games.

6 0
3 years ago
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