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4 years ago

Give a description of a 3/4-turn of the minute hand in a clock face. Please help it :(

Mathematics

2 answers:

Simora [160]4 years ago

5 0

45 min is the answer to your question

ollegr [7]4 years ago

3 0

It is 45 minutes
Hope dis helped m8

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Roger is a florist who uses a triangular-shaped frame to arrange flower bouquets. He received an order to make a new bouquet suc

kvv77 [185]

The locations specified in the order regarding the shape will be B. longest side AC; smallest angle ∠C.

<h3>How to express the information?</h3>

From the information given, in the triangle where A = 59°, B is unknown, and C = 41°. Therefore, the value of B will be:

= 180° - (59° + 41°)

= 180° - 100°

= 80°

Therefore, the locations specified in the order regarding the shape will be longest side AC; smallest angle ∠C.

In conclusion, the correct option is B.

Learn more about shapes on:

brainly.com/question/25965491

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4 0

2 years ago

Suppose the only measuring cup you own is a one-third measuring cup. Using this measuring cup how many scoops will you need to h

Mariulka [41]

Answer:

Step-by-step explanation:

for each full cup of sugar, you need 3 one-third measuring cups.

we have 3 full cups so 3×3=9

and another 2 for the 2/3, 9+2=11

so a total of 11 scoops

5 0

2 years ago

Given the inverse variation equation y=24/x, as the value of x increases, what does the value of y approach? (An exact number)

LenKa [72]

As x approaches positive infinity y approaches 0.

8 0

3 years ago

How is a rate simile do different from a ratio?

murzikaleks [220]

Both rates and ratios are a comparison of two numbers. A rate is a specific type of ratio. The difference is that a rate is a comparison of two numbers with different units, and a ratio compares two numbers with the same unit.

6 0

3 years ago

Find all zeros of f(x)=x^4-3x^3+6x^2+2x-60 given that 1+3i is a zero of f(x)

Triss [41]

Answer:

The roots of f(x) are: -2, 3, (1+3i) and (1-3i)

Step-by-step explanation:

We are given an expression:

$f(x)=x^4-3x^3+6x^2+2x-60$

(1+3i) is a root of f(x)

We have to find the remaining roots of f(x).

Since, (1+3i) is a root of f(x),

$x-(1+3i)$

is a factor of given expression.

Now, we check if (1 - 3i) is a root of given function.

$f(x)=x^4-3x^3+6x^2+2x-60\\f(1-3i)=(1-3i)^4-3(1-3i)^3+6(1-3i)^2+2(1-3i)-60\\= (28+96i)-3(-26+18i)+6(-8-6i)+2(1-3i)-60 = 0$

Thus, (1-3i) is also a root of given function.

Since, (1-3i) is a root of f(x),

$x-(1-3i)$

is a factor of given expression.

Thus, we can write:

$(x-(1+3i))(x-(1-3i))\text{ is a factor of f(x)}\\x^2-x(1-3i)+x(1+3i)+(1-3i)(1+3i)\text{ is a factor of f(x)}\\x^2-2x+10\text{ is a factor of f(x)}$

Dividing f(x) by above expression:

$\displaystyle\frac{x^4-3x^3+6x^2+2x-60}{x^2-2x+10} = x^2-x-6$

To find the root, we equate it to zero:

$x^2-x-6 = 0\\x^2 - 3x+2x-6=0\\x(x-3)+2(x-3)=0\\(x+2)(x-3) = 0\\x = -2, x = 3$

Thus, the roots of f(x) are: -2, 3, (1+3i) and (1-3i)

4 0

4 years ago