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4 years ago

If you move point toward point B along BC how does m_ABC change? How do mZBAC and mZACB change? What happens to these

Mathematics

1 answer:

Lilit [14]4 years ago

4 0

Answer:

i think its abc stays same, bac gets smaller, and acb gets bigger

for the second part, abc same, bac bigger, acb smaller

Step-by-step explanation:

if you picture the triangle in your head that probably would help

You might be interested in

Can a composite number have more than 3 factors

algol [13]

Yes it could have more because a composite# is a number that can be divodee it numbers more then it self

4 0

3 years ago

A random sample of n measurements was selected from a population with unknown mean mu and standard deviation sigmaequals50 for e

Andre45 [30]

Answer:

a) (26.50;57.50)

b) (117.34;128.66)

c) (12.13;27.87)

d) (-4.73;11.01)

e) No. Since the sample sizes are large (n ≥ 30), the central limit theorem guarantees that $\bar x$ is approximately normal, so the confidence intervals are valid

Step-by-step explanation:

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

And for a 95% of confidence the significance is given by $\alpha=1-0.95=0.05$ , and $\frac{\alpha}{2}=0.025$ . Since we know the population standard deviation we can calculate the critical value $z_{0.025}= \pm 1.96$

Part a

$n=40,\bar X=42,\sigma=50$

If we use the formula (1) and we replace the values we got:

$42 - 1.96 \frac{50}{\sqrt{40}}=26.50$

$42 + 1.96 \frac{50}{\sqrt{40}}=57.50$

The 95% confidence interval is given by (26.50;57.50)

Part b

$n=300,\bar X=123,\sigma=50$

If we use the formula (1) and we replace the values we got:

$123 - 1.96 \frac{50}{\sqrt{300}}=117.34$

$123 + 1.96 \frac{50}{\sqrt{300}}=128.66$

The 95% confidence interval is given by (117.34;128.66)

Part c

$n=155,\bar X=20,\sigma=50$

If we use the formula (1) and we replace the values we got:

$20 - 1.96 \frac{50}{\sqrt{155}}=12.13$

$20 + 1.96 \frac{50}{\sqrt{155}}=27.87$

The 95% confidence interval is given by (12.13;27.87)

Part d

$n=155,\bar X=3.14,\sigma=50$

If we use the formula (1) and we replace the values we got:

$3.14 - 1.96 \frac{50}{\sqrt{155}}=-4.73$

$3.14 + 1.96 \frac{50}{\sqrt{155}}=11.01$

The 95% confidence interval is given by (-4.73;11.01)

Part e

No. Since the sample sizes are large (n ≥ 30), the central limit theorem guarantees that $\bar x$ is approximately normal, so the confidence intervals are valid

8 0

3 years ago

Write an equation of the line in slope-intercept form. (0,-2), (3,3)

Leto [7]

Answer:

Step-by-step explanation:

m= y2-y1/x2-x1

m= 3-(-2)/ 3-0

m=5/3

y=mx+b

3= 5/3(3)+b

3= 5+b

-5 -5

-2=b

3 0

3 years ago

Which is the solution set of a for -3(-x + a) + 7 < 5 when x = -1?

damaskus [11]

Answer:

Step-by-step explanation:

-3 (-1+a)+7 <5

3-3a+7 <5

-3a+10 <5 (collect like terms )

-3a <-10+5

-3a <-5(divide both side by -3)

-3a/-3 <-5/-3

a>5/3

6 0

4 years ago

I need help with my homework please answer this correctly I don’t need wrong answers

enyata [817]

Well the 10,000 digit will be 1 and the thousand digit = 7 + 1 = 8

so the first 2 digits are 18

6 fewer than 8 = 2 so we get 182

1 fewer 10 than 1000's is 8-1 = 7 so we have 1827

and 5 fewer ones than 1000.s = 8 - 5 = 3

So our number is 18,273

6 0

3 years ago

Read 2 more answers