Answer:
D(-7,-2)
Step-by-step explanation:
A(-4,3) B(5,-1) C(-2,-6) D(-7,-2)
A: 5×(-4) + 6×3 = -2 ≥ -30 ..... No
B: 2/3×5 + 1 =4.33 ≥ -1 ....No
C: -6 ≤ 2/3×-2 +1 ....No
D: 2/3×(-7)+1 = 2.333 ≤ -2
5×(-7) + 6×(-2) = -47 ≤ -30 ......Yes
Part 1:
Fixed Cost, f = $20
number of balls = n
Cost of each ball, c = 4.32
Price of each ball, p = 8.32
Equation for total cost:
Total Cost of balls will come by adding the cost of all balls and the fixed cost
Total Cost = number of balls made × Cost of each ball + fixed cost
<em>C = 4.32n + 20</em>
Equation for revenue:
Revenue = Number of balls made × price of each ball
<em>R = 8.32n </em>
Part 2:
Use the graphing method to determine how many balls must be sold to break even
Breakeven means Revenue = total Cost
This happens at a point (5,41.6) where n = 5 is the number of balls sold
and C = 41.6 is the total cost
When 5 balls are sold there will be breakeven
R = 4n - 20
C = 4.32n + 20
Red line represent Cost
Black line represent Revenue
Answer:
4
Step-by-step explanation:
as it is an upward curve
The answer is <span>A)(13, 8).
Distance I to F is: yf - yi = -1 - (-4) = -1 + 4 = 3
Distance D to A is: ya - yd = 8 - 2 = 6
</span>Distance D to A : Distance I to F = 6 : 3<span>
6 : 3 = 2, so scale factor is 2.
Among all choices, we see that the y point of another corner is 8, so we need to find x point.
Distance I to H is: xh - xi = -2 - (-7) = -2 + 7 = 5
Distance A to x corner is: x - xa = x - 3
Since </span>Distance I to H is 5, and scale factor is 2, we have:
Distance A to x corner : Distance I to H = 2
Distance A to x corner = 2 * Distance I to H = 2 * 5 = 10
Distance A to x corner is: xa - x = x - 3 = 10
x - 3 = 10
x = 10 + 3
x = 13
The radius of tire is larger than radius of wheel by 5 inch
Step-by-step explanation:
We know that circumference of the circle is 2πr where “r” is the radius of the circle
Circumference refers to the dimension of the periphery of the circle. Since tires are put on the periphery of the wheel hence, we considered the circumferential aspect of the wheel.
Given-
Circumference of tires= 28π inches
2πr= 28π cancelling the common term “π” both sides
r (radius of the tires) = 14 inches
Circumference of the wheel rims= 18π
2πr= 18π cancelling the common term “π” both sides
r (radius of the tires) = 9 inches
Difference between the radius= 14-9= 5 inches
Hence, the difference between the radius of tires and the radius of the wheels is 5 inches