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snow_tiger [21]
3 years ago
8

What is the best approximation of the surface area of this right cone

Mathematics
1 answer:
Tatiana [17]3 years ago
4 0
Use the formula for the surface area of a right cone:

\sf A=\pi rs+\pi r^2

Where 'r' is the radius and 's' is the slant height, plug in what we know(use 3.14 to approximate for pi):

\sf A=(3.14)(12)(15)+(3.14)(12)^2

Multiply and simplify exponent:

\sf A=565.2+(3.14)(144)

Multiply:

\sf A=565.2+452.16

Add, round to the nearest whole number:

\boxed{\sf A\approx 1017~cm^2}
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Answer:

  arc DB length = 14π feet

Step-by-step explanation:

Assuming point A is the center of the circle, arc DC has measure 180°. Arc DB has measure 40° less, so is 140°. Since you want this in terms of π, we need to convert the degree measure to radians. We do that by multiplying by (π/180) radians per degree:

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The logarithm of a quotient can be written as a difference of logarithms:

\log_3\left(\dfrac uv\right) = \log_3(u) - \log_3(v)

You can also think of this as a combination of the product-to-sum and reciprocal/power properties of logarithms:

\log_3\left(\dfrac uv\right) = \log_3\left(u \times \dfrac1v\right) = \log_3(u) + \log_3\left(\dfrac1v\right) = \log_3(u) - \log_3(v)

To summarize,

\log_b(mn) = \log_b(m)+\log_b(n)

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