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Harman [31]
3 years ago
15

which of the following lengths cannot be the lengths of a triangle? 4,6,9 a.) 3,4,2 b.) 2,2,3 c.) 1,1,2 d.)

Mathematics
1 answer:
tamaranim1 [39]3 years ago
6 0

Answer:

D. 1, 1, 2

Step-by-step explanation:

A triangles sides have to have the two smallest side's sum add up to be greater than the largest number. In D, 1+1 = 2, and 2 is the largest number, since 2 is not greater than 2, It cannot be a triangle.

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Answer:

Step-by-step explanation:

Equation given

tan(3B-32 ) = cot ( 5B +10 ) = tan [ 90 - ( 5B + 10 ) ]

tan(3B-32 ) = tan  (90 - 5B - 10 )

(3B-32 ) =  (90 - 5B - 10 )

8B = 32 + 80

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5 0
3 years ago
More help... please... I'm very stuck​
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You just have to add or subtract the percent of a number from the original

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3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
noname [10]

L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)

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L_z=2+4\lambda z=0\implies1+2\lambda z=0

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There are two critical points, at which we have

f\left(2,2,1\right)=42\text{ (a maximum value)}

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4 years ago
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With what????????????????????
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Read 2 more answers
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