Solve for y and then graph it on a graphing calculator or since it doesn’t have a exponent you know it’s just a line because it would be the like y=4 which is a horizontal line at 4
No because when you do 3*--9 = 27 and 4*--12 =48
Answer:
bigger angle is 117°
Step-by-step explanation:
x+x+54= 180 (when two angles are complementary it means that their sum is 180 degrees)
2x+54=180
2x= 180-54
2x=128
x=126/2
x= 63
x1= smaller angle
x1= 63
x2= bigger angle
x2= 63+54
x2=117
Answer:
#carry on learning
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
By:
I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
Answer:
-sqrt(3) -i = 2 cis (7pi/6)
Step-by-step explanation:
-sqrt(3) -i
We can find the radius
r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)
= sqrt( 3 + 1)
= sqrt(4)
= 2
theta = arctan (y/x)
arctan (-1/-sqrt(3))
arctan (1/sqrt(3))
theta = pi/6
But this is in the first quadrant, and we need it in the third quadrant
Add pi to move it to the third quadrant
theta = pi/6 + 6pi/6
=7pi/6
-sqrt(3) -i = 2 cis (7pi/6)
