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podryga [215]
4 years ago
10

Please help me out I need help so bad

Mathematics
1 answer:
wel4 years ago
5 0

the answer is definitly C

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-28 = -7(3x + 4) +21x
Vlada [557]

Answer:

1 Expandir.

-28=-21x-28+21x

−28=−21x−28+21x

2 Simplifica  -21x-28+21x−21x−28+21x  a  -28−28.

-28=-28

−28=−28

3 Ya que ambos lados son iguales, hay infinitas soluciones.

Soluciones Infinitas

Step-by-step explanation:

7 0
3 years ago
How to do this problem
Vera_Pavlovna [14]
X(x-1)(x^2+4)=(x^2-x)(x^2+4)=(x^4)+(4x^2)-(x^3)-(4x)=(x^4)-x(x^2+4)+(4x^2)
6 0
3 years ago
Simplify the rational expression 6x-24/16-x^2
8_murik_8 [283]
The answer would be -x^2 + 6x  - 3/2
5 0
3 years ago
Read 2 more answers
Suppose you have an isosceles triangle with a 90° angleIf the congruent sides each measure 9 feet, what is the length of the sid
Zepler [3.9K]

Answer:

9\sqrt{2} feet

Step-by-step explanation:

Consider the attached figure.

An isosceles triangle is a triangle in which two sides are equal.

AB=BC=9 feet

According to Pythagoras theorem,

square of hypotenuse is equal to sum of squares of other two sides.

AC^2=AB^2+BC^2\\AC^2=9^2+9^2\\AC^2=81+81\\AC^2=162\\AC=\sqrt{162}

AC=9\sqrt{2} feet

6 0
3 years ago
Find five consecutive integers such that the sum of the first and 5 times the third is equal to 41 less than 3 times the sum of
bogdanovich [222]

Answer:

see below

Step-by-step explanation:

We'll cal the first integer x and then the rest of them will be x + 1, x + 2, x + 3 and x + 4. We can write x + 5(x + 2) = 3(x + 1 + x + 3 + x + 4) - 41.

x + 5x + 10 = 3(3x + 8) - 41

6x + 10 = 9x + 24 - 41

6x + 10 = 9x - 17

3x = 27

x = 9

The numbers are 9, 10, 11, 12, 13.

6 0
3 years ago
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