Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.
Answer:
Step-by-step explanation:
∠CAB = 33 {alternate interior angles}
5x = 33 + 2x { exterior angle equals sum of opposite interior angles}
5x - 2x = 33
3x = 33
x = 33/3
x = 11
∠B = 2x = 2* 11 = 22
∠ECB = 5x = 5*11 = 55
Answer:
19
Step-by-step explanation:
3x+4 while x is 5 means (3*5)+4 so 15+4=19
If that's not what you wanted I am sorry.
Answer:
True
Step-by-step explanation:
In order for a relation (a set of ordered pairs) to be considered a <em>function</em>, every value in the <em>domain</em> (the set of all the first numbers in the pair) is associated with one value in the <em>range</em> (the set of all second numbers in the pair). This is easiest to see visually. Our domain is the set {2, 3, 4, 5} and our range is the set {4, 6, 8, 10}, and we can visualize the ordered pair (2, 4) as an "arrow" starting a 2 in the domain and ending at 4 in the range. When seen this way, a relation is a function if <em>every value in the domain only has one arrow coming out of it</em>. We can see from the attached picture that the ordered pairs in the problem are a function, so this statement is true.