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2 years ago

HELP PLEASE!! URGENT!!

Mathematics

1 answer:

Ugo [173]2 years ago

5 0

Answer:

Step-by-step explanation:

You can answer this using the law of cosines:

$c^2=a^2+b^2-2ab \cos{c}$

c^2 is equal to 4^2 + 7^2 - 2(4)(7)(cos 102º)

= 16 + 49 - 56(cos 102º)

c^2 ~ 76.64 --> c ~ 8.8

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If f(x) = -2x + 7, find f(8)

anastassius [24]

Answer:

-9

Step-by-step explanation:

You have to plug 8 into the formula for x. f(8) = -2(8)+7 = -16+7 = -9

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3 years ago

PLEASE HELP mathematics

AlexFokin [52]

Answer:

21+10.5 which would equal 31.5

Step-by-step explanation:

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2 years ago

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Factor completely 4h2 + g.

stiv31 [10]

Answer:

8h + g

Step-by-step explanation

When you say "4h2", do you mean 4h multiplied by 2?

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2 years ago

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The midpoint of the coordinates (3, 15) and (20,8) is -

Nat2105 [25]

Answer:

The midpoint of the given coordinates is $(\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5)$ .

Step-by-step explanation:

We have given two coordinates (3,15) and (20,8).

Let we have given a line segment PQ whose P coordinate is (3,15) and Q coordinate is (20,8).

We have to find out the mid point M(x,y) of the line segment PQ.

Solution,

By the mid point formula of coordinates, which is;

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

On substituting the given values, we get;

$M(x,y)=(\frac{3+20}{2}, \frac{15+8}{2})\\\\M(x,y)=(\frac{23}{2},\frac{23}{2})$

We can also say that $M(x,y)=(11.5,11.5)$

Hence The midpoint of the given coordinates is $(\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5)$ .

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2 years ago

If a, b, and care digits for which the following holds, then a +b+c=.

Ugo [173]

Answer:

Step-by-step explanation:

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3 years ago