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So I'm assuming that you're taking Calculus.
The first thing you want to do is take the integral of f(x)...
Use the power rule to get:
4X^2-13X+3.
Now solve for X when f(x)=0. This is because when the slope is 0, it is either a minimum or a maximum(I'm assuming you know this)
Now you get X=0.25 and X=3. Since we are working in the interval of (1,4), we can ignore 0.25
Thus our potential X values for max and min are X=1,X=4,X=3(You don't want to forget the ends of the bounds!)
Plugging these value in for f(x), we get
f(1)=2.833
f(3)=-8.5
f(4)=1.667
Thus X=1 is the max and X=3 is the min.
So max:(1,2.833)
min:(3,-8.5)
Hope this helps!
The absolute value is the value of the number without the sign. So in this case it's 3 and -3
Answer:
20 homes
Step-by-step explanation:
Given that :
Total number of homes = 800
Average years at which homes are listed = 8 years
To obtain the annual home listing = total number of Homes / average years
Annual home listing = 800 / 8
Annual home listing = 100 homes
If 20% of the homes are listed on the year in question :
20% of 100 homes
0.2 * 100
= 20 homes
20 homes can be listed that year
Four children average is 15.25 so ages must add to 61
61-12-16=33
11 and 22 go into 33
Youngest is 11
