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Amiraneli [1.4K]
1 year ago
6

Solve 5! how do i solve 5 with legit 0 context?

Mathematics
1 answer:
Yakvenalex [24]1 year ago
8 0

Answer:

5! = 120

Step-by-step explanation:

using the definition of factorial !

n! = n(n - 1)(n - 2) .... 3 × 2 × 1 , then

5! = 5 × 4 × 3 × 2 × 1 = 20 × 12 × 1 = 120

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iragen [17]
(_/18+2_/3)^(2

=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)

=18+ 12_/6 +12

=30+12_/6

hope this helps

3 0
3 years ago
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Answer:

3

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Answer:

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3 0
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