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nasty-shy [4]
3 years ago
8

How can you use the transformation to prove two triangles are congruent

Mathematics
1 answer:
Alla [95]3 years ago
6 0
You could use a translation to move one to the same position as the other and compare if they have the same orientation (like both are pointing up).
If not, you could use rotation to do so, then use translation. Sometimes even reflections might work, but that's a bit more complex.
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0.02km, 50m,3000cm least to greatest
Vsevolod [243]
0.02km (least)
3000cm
50m (greatest)
4 0
3 years ago
What is the slope of 3x+8y-1=0
Fudgin [204]
One of the most common ways to find the slope is to put the problem in standard, slope-intercept form, which is y=mx+b. The easiest way to describe this process is to isolate y.
Here's how you do it for this problem:
3x+8y-1=0 \\ (3x+8y-1)+1=(0)+1 \\ 3x+8y=1 \\ (3x+8y)-3x=(1)-3x \\ 8y=-3x+1 \\ (8y)/8=(-3x)/8+(1)/8 \\ y= -\frac{3}{8}x+ \frac{1}{8}
Since m is your slope, the answer would be -3/8.
Hope this helps!
7 0
4 years ago
the median weekly earnings for american workers in 1990 was $412 and in 1999 it was $549. Calculate the average rate of change b
mina [271]

The rate of change between 1990 and 1999 is 15.22

Step-by-step explanation:

The rate of change in this case is given by change in quantity divided by change in time

So,

Rate\ of\ change = \frac{Increase\ in\ money}{Increase\ in\ time}\\=\frac{549-412}{1999-1990}\\=\frac{137}{9}\\=15.22

Hence,

The rate of change between 1990 and 1999 is 15.22

Keywords: Rate of change, median

Learn more about median at:

  • brainly.com/question/10764770
  • brainly.com/question/1087090

#LearnwithBrainly

5 0
3 years ago
Which are the roots of the quadratic function f(q) = q^2 - 125? Select two options.
liubo4ka [24]

Answer:

None of the options are correct

Step-by-step explanation:

Given

f(q) = q^2 - 125

Required

The roots of the function

Since the function is a quadratic function; to get the roots of the function, f(q) must be equal to 0

f(q) = q^2 - 125 becomes

0 = q^2 - 125

Make q^2 the subject of formula

125= q^2

Rearrange

q^2 = 125

Take square roots of both sides

\sqrt{q^2}  = \sqrt{125}

q  = \sqrt{125}

Expand the square root of 125

q  = \sqrt{25 * 5}

q  = \sqrt{25} * \sqrt{5}

q = ±5 * \sqrt{5}

Split into 2

q  = 5 * \sqrt{5} or q  = -5 * \sqrt{5}

q  = 5  \sqrt{5} or q  = -5 \sqrt{5}

Hence, the roots of the quadratic function are q  = 5  \sqrt{5} or q  = -5 \sqrt{5}

5 0
4 years ago
Read 2 more answers
MULTIPLE CHOICE PLS HELP! (Links = report)
Elena-2011 [213]

Answer:

Option 1.

3,619.1 m^3

Step-by-step explanation:

Mark as brainliest if this helped :D

3 0
3 years ago
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