6. There are 90 seats in the school auditorium. The school had a sold out show of their play last weekend, and made $315. The co
1 answer:
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Answer: Probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.
Step-by-step explanation:
Since we have given that
Mean rate defects per unit = 0.3
Since we will use "Poisson distribution":
But we need to find the probability that a randomly selected unit will contain at least two surface-finish defect.
So,
so, it becomes,
Hence, probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.
Answer:
(1)0.0138
(2)A. If the depth of the dive is increased by one meter, it adds 0.0138 minutes to the time spent under water.
Nos 3-12: See Explanation
Step-by-step explanation:
Given the regression equation for the relation of dive duration (DD) to depth (D).
(1)The slope of the regression lie =0.0138
(2)
When D=1, DD = 2.69 + 0.0138(1)=2.7038
When D=2, DD = 2.69 + 0.0138(2)=2.7176
2.7176-2.7038=0.0138
Therefore, If the depth of the dive is increased by one meter, it adds 0.0138 minutes to the time spent under water.
(3) When depth, D =200 meters
DD = 2.69 + 0.0138(200)=5.45 Minutes
(4) When depth, D =210 meters
DD = 2.69 + 0.0138(210)=5.588 Minutes
(5) When depth, D =220 meters
DD = 2.69 + 0.0138(220)=5.726 Minutes
(6) When depth, D =230 meters
DD = 2.69 + 0.0138(230)=5.864 Minutes
(7) When depth, D =240 meters
DD = 2.69 + 0.0138(240)=6.002 Minutes
(8) When depth, D =150 meters
DD = 2.69 + 0.0138(150)=4.76 Minutes
(9) When depth, D =160 meters
DD = 2.69 + 0.0138(160)=4.898 Minutes
(10) When depth, D =170 meters
DD = 2.69 + 0.0138(170)=5.036 Minutes
(11) When depth, D =180 meters
DD = 2.69 + 0.0138(180)=5.174 Minutes
(12) When depth, D =190 meters
DD = 2.69 + 0.0138(190)=5.312 Minutes