Answer:
The barge can carry up to 94 railroad cars.
Step-by-step explanation:
Create an inequality to represent the weight of the barge to the max weight.
24 + 4r ≤ 400
Solve for r:
4r ≤ 400 - 24
4r ≤ 376
4r ≤ 376/4
r ≤ 94
121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range

The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.
The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:

So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range

That's probably the answer they're looking for.
Answer: 
Step-by-step explanation:
Given
The height of the cylinder is 
The volume of the cylinder is 
The volume of the cylinder is the product of area and height

Insert the values

Thus, the area of the cross-section is 
Answer:
B.) 132.56 degrees
Step-by-step explanation:
Answer:
48 yr. old
Step-by-step explanation:
Assume daughter is 4 and mom is 10 times her age, so mom is 40.
10 (woman) * 4 (daughter's age) = 40 yr. old mom
Present day...
40 (yr old mom) + 8 (yrs later) = 48 yr. old mom today
4 (yr old daughter) + 8 (yrs later) = 12 yr. old daughter today
So, if mom is 4 times as her daughter's age today...
48 (yr. old mom) / 12 (yr. old daughter) = 4