The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation 
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2=0
=> =0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
#SPJ1
The answer might be B, but realize if a circle is shifting both y and x can’t decrease.. and both cant increase at the same time.
Answer:
20
Step-by-step explanation:
Riyas score = ( correct answer × mark) + ( incorrect answer × mark lost )
= ( 3× 10) + ( -1 ×10 )
= 30 -10
=20
A)
Exact Form:
−31/3
Decimal Form:
−10.33333
Mixed Number Form:
-10 1/3
b)
Exact Form:
17/12
Decimal Form:
1.416666
Mixed Number Form:
1 5/12
She added the check fee instead of subtracting it
