Since sin(2x)=2sinxcosx, we can plug that in to get sin(4x)=2sin(2x)cos(2x)=2*2sinxcosxcos(2x)=4sinxcosxcos(2x). Since cos(2x) = cos^2x-sin^2x, we plug that in. In addition, cos4x=cos^2(2x)-sin^2(2x). Next, since cos^2x=(1+cos(2x))/2 and sin^2x= (1-cos(2x))/2, we plug those in to end up with 4sinxcosxcos(2x)-((1+cos(2x))/2-(1-cos(2x))/2)
=4sinxcosxcos(2x)-(2cos(2x)/2)=4sinxcosxcos(2x)-cos(2x)
=cos(2x)*(4sinxcosx-1). Since sinxcosx=sin(2x), we plug that back in to end up with cos(2x)*(4sin(2x)-1)
Answer:
1/4x (8 x - 15)
Step-by-step explanation:
write the division as a fraction
1/2x + 3/2x (x - 5 ÷ 2)
factor out 1/2 from the expression.
1/2x(x + 3(x - 5 ÷ 2))
divide the numbers.
1/2x(x + 3(x - 2.5))
distribute 3 through the parentheses.
1/2x(x + 3x - 7.5)
collect like terms.
1/2x(4x - 7.5)
1/2x(4x - 15/2)
factor out 1/2 from the expression.
1/2 x 1/2 x (8 x - 15)
multiply the fractions
= 1/4 x (8x - 15)
or alternative form
= 0.25(8x - 15)
Answer:
13909416897778.08 cm
Step-by-step explanation:
Answer:
c-5
Step-by-step explanation:
