Answer:
1.753 g
Step-by-step explanation:
Half life of Einsteinium = 20.5 days
Time elapsed = 31 days
Initial quantity of the substance = 5g
The formula to apply is;
Where
N(t)=quantity of a substance remaining
No =Initial quantity of the substance = 5g
t= time elapsed=31 days
t1/2 = half life of the substance= 20.5 days
N(t)=5 * {1/2} ^ {31/20.5}
N{t} = 5 * {0.5}^1.5
N{t} = 5*0.3506
N{t} =1.753 g
12 lcm least common multiple 6x2=12 are you in rsm i had that same problem
Answer:
(0, 5), (1, 3), (2, 1), (3, -1), (4, -3)
Step-by-step explanation:
To find the possible solutions, we just plug in a random value for x and then solve for y. When x - 0, y = 5. When x = 1, y = 3. We just continue doing this until we have 5 different solutions.
Here is your answer. Hope you'll find it helpful. :)
1) the 3 measures of central tendency is mean, median, and mode.
So when finding the average clutch size is by using mean.
Clutch sizes:
114, 103, 121, 118, 107, 103, 104
114+103+121+118+107+103+104
=770
= 770 ÷ 7 ( 7 ⇒ there are seven numbers in total)
= 110
∴ Therefore the average clutch size is 110.
2) Through that table of data, yes, I think that the clutch size influences the survival rates of the offspring because it seems that when the clutch size is big, it is more likely for offspring to survive and return. Yet when the clutch size are small, for example, site E and G, the amount of turtles who returned are 40 and 38. But in site A, C, and D, there are 45 turtles in site A that returned, 55 turtles in site C, and 53 turtles in site D.
3) Possibly is because their clutch sizes are the smallest which made them unnoticeable to predators and more likely to survive and returned.
